Django 如果表单发生更改，则触发。德扬戈

我在票务系统工作时遇到问题。用户创建一个票证并将信息发送到他们的电子邮件中。当从管理面板更改票据时，如何发送新信息

型号：

class TroubleTicket(models.Model):
    title = models.CharField(max_length=200)
    name = models.CharField(max_length=200)
    address = models.CharField(choices=ADDRESSES, default=None,  
    max_length=200)
    room = models.CharField(max_length=50)
    message = RichTextUploadingField()
    state = models.CharField(choices=STATES, max_length=30,   
    default='New')
    answer = RichTextUploadingField(blank=True, null=True)
    email = models.CharField(max_length=200, blank=True, null=True)
    create_date = models.DateTimeField(auto_now_add=True)

    def __unicode__(self):
        return self.title

    def get_absolute_url(self):
        return reverse('ticket_detail', kwargs={'pk': self.id})

    class Meta:
        ordering = ['-create_date']

如果用户指定了邮件，则保存表单并发送邮件：

class CreateTicket(CreateView):
    template_name = 'incidentjournal/add_ticket.html'

    form_class = TicketForm
    model = TroubleTicket
    context_object_name = 'ticket'
    success_url = reverse_lazy('home')

    def form_valid(self, form):
        recipient = form.cleaned_data['email'].encode('utf8')
        new_ticket = form.save()
        new_ticket_id = new_ticket.pk
        address = new_ticket.address.encode('utf8')
        title = new_ticket.title.encode('utf8')
        name = new_ticket.name.encode('utf8')
        room = new_ticket.room.encode('utf8')

        send_to_email(recipient, str(new_ticket_id), title, address,  
        room, name)

        send_to_bot(str(new_ticket_id), title, address, room, name)

        return super(CreateTicket, self, ).form_valid(form)

如果状态或答案在管理面板中已更改，我想将更改发送给用户

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谢谢你的建议

如果

状态

更改意味着该特定票据是否已正确更新？所以，当有变化时，为什么不使用UpdateView发送电子邮件呢。你试过类似的东西吗？看看文档。这应该是一个解决办法。