django Rest框架-带有自定义列表视图和URL参数的视图集

我有以下设置：

我想列出一年中所有的假期。这就是为什么我不使用默认列表视图，而是像这样实现自己的列表视图：

class HolidayViewSet(mixins.RetrieveModelMixin, GenericViewSet):
@list_route()
def year(self, request, year=get_today().year):
    public_holidays = self.get_queryset().filter(date__year=year)
    page = self.paginate_queryset(public_holidays)
    if page is not None:
        serializer = self.get_serializer(page, many=True)
        return self.get_paginated_response(serializer.data)
    serializer = self.get_serializer(public_holidays, many=True)
    return Response(serializer.data)

class TestListView(generics.ListAPIView):
    serializer_class = TestSerializer

    def get(self, request, *args, **kwargs):
        year = kwargs.get('year', '')
        query_set = Test.objects.filter(year__exact=year) # Test is my test model
        serializer = self.get_serializer(query_set, many=True)
        return Response(serializer.data)

如果我使用默认值/假日/年份/我会得到当前年份的结果

但当我试图传递一个参数时，我会得到一个404。404页面（在调试模式下）甚至向我显示了正确的URL模式：

api/v1/ ^holiday/year/$ [name='holiday-year']
api/v1/ ^holiday/year\.(?P<format>[a-z0-9]+)/?$ [name='holiday-year']

api/v1/^holiday/year/$[name='holiday-year']
api/v1/^holiday/year\（？P[a-z0-9]+）/？$[name='holiday-year']

不幸的是，在本报告中，这一方面没有涉及

你知道为什么我去2017年假日的路线不起作用吗

谢谢！

---

Ron

DRF区分了

列表

和

细节

请求<代码>列表请求不应有额外的路径参数（即

/{id}

），而

细节

请求则由它定义

---

它的意思是，装饰者创建

@list\u-route

端点，而

@detail\u-route

将创建

/holiday/{id}/year

端点。

好的，我的解决方法是使用

django筛选器

我的过滤器：

class HolidayFilter(filters.FilterSet):
    """
    This filter can be used to filter holidays by different values in API views or viewsets.
    See http://django-filter.readthedocs.io/en/1.1.0/guide/rest_framework.html
    """
    year = filters.NumberFilter(name='date', lookup_expr='year')

    class Meta:
        model = Holiday
        fields = ['date']

class HolidayListViewSet(ModelViewSet):

    def list(self, request, *args, **kwargs):
        # Apply filters
        queryset = self.filter_queryset(self.get_queryset())
        page = self.paginate_queryset(queryset)
        # Pagination
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)
        # Serializer
        serializer = self.get_serializer(queryset, many=True)
        # Response
        return Response(serializer.data)

/api/v1/holiday/?year=2016

我的视图集：

class HolidayFilter(filters.FilterSet):
    """
    This filter can be used to filter holidays by different values in API views or viewsets.
    See http://django-filter.readthedocs.io/en/1.1.0/guide/rest_framework.html
    """
    year = filters.NumberFilter(name='date', lookup_expr='year')

    class Meta:
        model = Holiday
        fields = ['date']

class HolidayListViewSet(ModelViewSet):

    def list(self, request, *args, **kwargs):
        # Apply filters
        queryset = self.filter_queryset(self.get_queryset())
        page = self.paginate_queryset(queryset)
        # Pagination
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)
        # Serializer
        serializer = self.get_serializer(queryset, many=True)
        # Response
        return Response(serializer.data)

/api/v1/holiday/?year=2016

网址：

class HolidayFilter(filters.FilterSet):
    """
    This filter can be used to filter holidays by different values in API views or viewsets.
    See http://django-filter.readthedocs.io/en/1.1.0/guide/rest_framework.html
    """
    year = filters.NumberFilter(name='date', lookup_expr='year')

    class Meta:
        model = Holiday
        fields = ['date']

class HolidayListViewSet(ModelViewSet):

    def list(self, request, *args, **kwargs):
        # Apply filters
        queryset = self.filter_queryset(self.get_queryset())
        page = self.paginate_queryset(queryset)
        # Pagination
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)
        # Serializer
        serializer = self.get_serializer(queryset, many=True)
        # Response
        return Response(serializer.data)

/api/v1/holiday/?year=2016

---

谢谢你的支持，也许这对其他人有帮助

我认为我的方法很简单，但很有用。只需按如下方式确定您的路由器：

urlpatterns += [
    path(r'holiday/<int:year>/', TestListView.as_view()),
]

---

检查这个问题：谢谢，但这似乎不是一个干净的解决方案。您使用的是一个非常过时的DRF文档版本。您的Django REST框架版本是什么？这一部分解释了如何构建URL：感谢您的输入。但django告诉我已经有了一条路线。我想使用它而不需要创建单独的路由。好吧，关于404页面，我得到了我想要的路由。即使使用列表和路径。但是我怎么用呢？@Ron“我想走哪条路就走哪条路”——不完全是这样<代码>^holiday/year\（？P[a-z0-9]+）/？$生成格式为

holiday/year.[a-z0-9]+

的路径。不

holiday/year/{id}

我知道。但不幸的是——正如我所指出的——我无法使用这条路线。我没有试身份证，我试了好几年。