elasticsearch 将GeoJSON字符串转换为Elasticsearch几何体
我有一个像这样的GeoJSON字符串elasticsearch 将GeoJSON字符串转换为Elasticsearch几何体,elasticsearch,geometry,geojson,elasticsearch,Geometry,Geojson,我有一个像这样的GeoJSON字符串 { "type": "Polygon", "coordinates": [ [ [ 121.4, 33.99831528411953 ], [ 120.32770211588034,
{
"type": "Polygon",
"coordinates": [
[
[
121.4,
33.99831528411953
],
[
120.32770211588034,
33.09540949748297
],
[
121.4,
32.20168471588049
],
[
122.47229788411967,
33.09540949748297
],
[
121.4,
33.99831528411953
]
]
]
}
我想将其转换为Elasticsearch几何体或ShapeBuilder
但是我没有找到一个方便的方法
有没有人遇到过类似的问题
或者让工具类可以做到这一点
非常感谢以下是您可以做到这一点的方法:
// read your GeoJSON string from a file
String geojson = ...;
// parse the GeoJSON
JsonXContent geoJsonParser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, LoggingDeprecationHandler.INSTANCE, geojson);
// create a shape builder (of type PolygonBuilder since the GeoJSON represents a polygon)
PolygonBuilder shapeBuilder = (PolygonBuilder) ShapeBuilder.parse(geoJsonParser);
以下是如何做到这一点:
// read your GeoJSON string from a file
String geojson = ...;
// parse the GeoJSON
JsonXContent geoJsonParser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, LoggingDeprecationHandler.INSTANCE, geojson);
// create a shape builder (of type PolygonBuilder since the GeoJSON represents a polygon)
PolygonBuilder shapeBuilder = (PolygonBuilder) ShapeBuilder.parse(geoJsonParser);
我找到了一个解决方案,比如
String valueAsString = mapper.writeValueAsString(value);
GeometryParser parser = new GeometryParser(true, true, true);
XContentParser contentParser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, DeprecationHandler.THROW_UNSUPPORTED_OPERATION, valueAsString);
contentParser.nextToken();
Geometry geometry = parser.parse(contentParser);
但是我不知道这是对还是错。我找到了一个类似这样的解决方案
String valueAsString = mapper.writeValueAsString(value);
GeometryParser parser = new GeometryParser(true, true, true);
XContentParser contentParser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, DeprecationHandler.THROW_UNSUPPORTED_OPERATION, valueAsString);
contentParser.nextToken();
Geometry geometry = parser.parse(contentParser);
但我不知道这是否正确。是否要将此GeoJSON解析为几何体/形状?是吗?是的,我正在使用Elasticsearch 7.5。是否要将此GeoJSON解析为几何体/形状?是吗?是的,我正在使用Elasticsearch 7.5。非常感谢您的回答。我认为这是正确的方法很酷,很高兴它有帮助!非常感谢你的回答。我认为这是正确的方法很酷,很高兴它有帮助!