Excel 如何检查带有for循环的单元格中的值是否相等?
我想检查单元格中的文本值是否与下面带有for循环的单元格中的文本值相同 如果单元格(1)和单元格(2)中的值不匹配,我希望单元格(3)中的值写入单元格(4) 我犯了一个错误 “溢出(错误6)” 我有一个生产输出和一个从早上6点到12点的时间表,我想创建一个时间表,如下所示 截图:Excel 如何检查带有for循环的单元格中的值是否相等?,excel,vba,for-loop,comparison,Excel,Vba,For Loop,Comparison,我想检查单元格中的文本值是否与下面带有for循环的单元格中的文本值相同 如果单元格(1)和单元格(2)中的值不匹配,我希望单元格(3)中的值写入单元格(4) 我犯了一个错误 “溢出(错误6)” 我有一个生产输出和一个从早上6点到12点的时间表,我想创建一个时间表,如下所示 截图: 这里我使用的是一个字典,它将存储每个产品的每次逗号分隔,因此稍后将拆分它并取第一次和最后一次出现的内容: Sub TimeTable() 'Declare an array variable to s
这里我使用的是一个字典,它将存储每个产品的每次逗号分隔,因此稍后将拆分它并取第一次和最后一次出现的内容:
Sub TimeTable()
'Declare an array variable to store the data
'change MySheet for your sheet name
arr = ThisWorkbook.Sheets("MySheet").UsedRange.Value 'this will store the whole worksheet, the used area.
'Declare a dictionary object
Dim Products As Object: Set Products = CreateObject("Scripting.Dictionary")
'Loop through the array
Dim i As Long
For i = 3 To UBound(arr) 'start from row 3 because of your screenshoot
If arr(i, 21) = vbNullString Then GoTo NextRow 'if column U is empty won't add anything
If Not Products.Exists(arr(i, 21)) Then '21 is the column index for column U
Products.Add arr(i, 21), arr(i, 1)
Else
Products(arr(i, 21)) = arr(i, 21) & "," & arr(i, 1)
End If
NextRow:
Next i
Erase arr
'Redim the array to fit your final data, 4 columns and as many rows as products
ReDim arr(1 To Products.Count + 1, 1 To 4)
'Insert the headers
arr(1, 1) = "Time"
arr(1, 4) = "Product / Error"
'Now loop through the dictionary
Dim Key As Variant, MySplit As Variant
i = 2
For Each Key In Products.Keys
MySplit = Split(Products(Key), ",")
arr(i, 1) = MySplit(LBound(MySplit))
arr(i, 2) = "-"
arr(i, 3) = MySplit(UBound(MySplit))
arr(i, 4) = Key
i = i + 1
Next Key
'I don't know where are you going to paste your data, so I'm making a new worksheet at the end of your workbook
Dim ws As Worksheet
Set ws = ThisWorkbook.Sheets.Add(After:=ThisWorkbook.Sheets(ThisWorkbook.Sheets.Count))
With ws
.Range("A1").Resize(UBound(arr), UBound(arr, 2)).Value = arr
.Range("A1:C1").Merge
End With
End Sub
在这里,我使用的是一个字典,它将每次存储的每个产品都用逗号分隔,因此稍后会将其拆分,并取第一次和最后一次出现的内容:
Sub TimeTable()
'Declare an array variable to store the data
'change MySheet for your sheet name
arr = ThisWorkbook.Sheets("MySheet").UsedRange.Value 'this will store the whole worksheet, the used area.
'Declare a dictionary object
Dim Products As Object: Set Products = CreateObject("Scripting.Dictionary")
'Loop through the array
Dim i As Long
For i = 3 To UBound(arr) 'start from row 3 because of your screenshoot
If arr(i, 21) = vbNullString Then GoTo NextRow 'if column U is empty won't add anything
If Not Products.Exists(arr(i, 21)) Then '21 is the column index for column U
Products.Add arr(i, 21), arr(i, 1)
Else
Products(arr(i, 21)) = arr(i, 21) & "," & arr(i, 1)
End If
NextRow:
Next i
Erase arr
'Redim the array to fit your final data, 4 columns and as many rows as products
ReDim arr(1 To Products.Count + 1, 1 To 4)
'Insert the headers
arr(1, 1) = "Time"
arr(1, 4) = "Product / Error"
'Now loop through the dictionary
Dim Key As Variant, MySplit As Variant
i = 2
For Each Key In Products.Keys
MySplit = Split(Products(Key), ",")
arr(i, 1) = MySplit(LBound(MySplit))
arr(i, 2) = "-"
arr(i, 3) = MySplit(UBound(MySplit))
arr(i, 4) = Key
i = i + 1
Next Key
'I don't know where are you going to paste your data, so I'm making a new worksheet at the end of your workbook
Dim ws As Worksheet
Set ws = ThisWorkbook.Sheets.Add(After:=ThisWorkbook.Sheets(ThisWorkbook.Sheets.Count))
With ws
.Range("A1").Resize(UBound(arr), UBound(arr, 2)).Value = arr
.Range("A1:C1").Merge
End With
End Sub
你可以用
Option Explicit
Sub test()
Dim LastRowA As Long, i As Long, j As Long, LastRowW As Long
Dim StartTime As Date, EndTime As Date, strOutPut
j = 0
With ThisWorkbook.Worksheets("Sheet1")
LastRowA = .Cells(.Rows.Count, "A").End(xlUp).Row
For i = 3 To LastRowA
If i > j - 1 Then
StartTime = .Range("A" & i).Value
strOutPut = .Range("U" & i).Value
For j = i + 1 To LastRowA + 1
If strOutPut <> .Range("U" & j).Value Then
EndTime = .Range("A" & j - 1).Value
LastRow = .Cells(.Rows.Count, "W").End(xlUp).Row
.Range("W" & LastRow + 1).Value = StartTime
.Range("X" & LastRow + 1).Value = EndTime
.Range("Y" & LastRow + 1).Value = strOutPut
Exit For
End If
Next j
End If
Next i
End With
End Sub
选项显式
子测试()
我长,我长,j长,我长
Dim StartTime As Date,EndTime As Date,strOutPut
j=0
使用此工作簿。工作表(“表1”)
LastRowA=.Cells(.Rows.Count,“A”).End(xlUp).Row
对于i=3至LastRowA
如果i>j-1那么
StartTime=.Range(“A”&i).Value
strOutPut=.Range(“U”&i).Value
对于j=i+1到最后一行a+1
如果strOutPut.Range(“U”&j).Value,则
EndTime=.Range(“A”&j-1).Value
LastRow=.Cells(.Rows.Count,“W”).End(xlUp).Row
.Range(“W”&LastRow+1)。值=开始时间
.Range(“X”&LastRow+1)。值=结束时间
.Range(“Y”&LastRow+1)。值=输出
退出
如果结束
下一个j
如果结束
接下来我
以
端接头
结果
您可以使用
Option Explicit
Sub test()
Dim LastRowA As Long, i As Long, j As Long, LastRowW As Long
Dim StartTime As Date, EndTime As Date, strOutPut
j = 0
With ThisWorkbook.Worksheets("Sheet1")
LastRowA = .Cells(.Rows.Count, "A").End(xlUp).Row
For i = 3 To LastRowA
If i > j - 1 Then
StartTime = .Range("A" & i).Value
strOutPut = .Range("U" & i).Value
For j = i + 1 To LastRowA + 1
If strOutPut <> .Range("U" & j).Value Then
EndTime = .Range("A" & j - 1).Value
LastRow = .Cells(.Rows.Count, "W").End(xlUp).Row
.Range("W" & LastRow + 1).Value = StartTime
.Range("X" & LastRow + 1).Value = EndTime
.Range("Y" & LastRow + 1).Value = strOutPut
Exit For
End If
Next j
End If
Next i
End With
End Sub
选项显式
子测试()
我长,我长,j长,我长
Dim StartTime As Date,EndTime As Date,strOutPut
j=0
使用此工作簿。工作表(“表1”)
LastRowA=.Cells(.Rows.Count,“A”).End(xlUp).Row
对于i=3至LastRowA
如果i>j-1那么
StartTime=.Range(“A”&i).Value
strOutPut=.Range(“U”&i).Value
对于j=i+1到最后一行a+1
如果strOutPut.Range(“U”&j).Value,则
EndTime=.Range(“A”&j-1).Value
LastRow=.Cells(.Rows.Count,“W”).End(xlUp).Row
.Range(“W”&LastRow+1)。值=开始时间
.Range(“X”&LastRow+1)。值=结束时间
.Range(“Y”&LastRow+1)。值=输出
退出
如果结束
下一个j
如果结束
接下来我
以
端接头
结果
您的
a
变量未声明:Dim a as Range
也未设置:set a=单元格(3+i,1)
。同时声明i
为Long
,而不是Integer
开始时,将替换为i=1的行数。用a来计算。不要使用Integer
变量(导致溢出非常容易),而是使用Long
。根据@Plution,也要使用更可靠的方法检索最后一行。此外,我建议至少使用一个工作表引用,并通过数组(通过内存)而不是单元格进行循环。话虽如此。请您提供一些模型样本数据和预期结果好吗?@Teamothy,我不认为变量是范围对象。相反,我认为OP试图编写Cells(228+j,3)=Cells(3+I,1)
@JvdV是的,我的错,他想要的是一个值而不是范围,采用你的方法会更容易。你的a
变量没有声明:将a作为范围变暗
也没有设置:设置a=单元格(3+I,1)
。同时声明i
为Long
,而不是Integer
开始时,将替换为i=1的行数。用a来计算。不要使用Integer
变量(导致溢出非常容易),而是使用Long
。根据@Plution,也要使用更可靠的方法检索最后一行。此外,我建议至少使用一个工作表引用,并通过数组(通过内存)而不是单元格进行循环。话虽如此。请您提供一些模型样本数据和预期结果好吗?@Teamothy,我不认为变量是范围对象。相反,我认为OP试图编写单元格(228+j,3)=单元格(3+I,1)
@JvdV是的,我的错,他想要的是一个值而不是范围,采用你的方法会更容易。