Flask 带数据库通信的socketio
我想做的是下一步:Flask 带数据库通信的socketio,flask,websocket,socket.io,flask-socketio,Flask,Websocket,Socket.io,Flask Socketio,我想做的是下一步: 第一次连接由客户进行(“连接”) 然后从Python中调用函数,该函数根据数据库中的信息,将emmit转换为另一个“套接字”(test) 但我的问题是,当数据库中有任何寄存器时,它会生成一个emmit来测试并显示“Youhavesomething!”,但当我从数据库中删除信息而数据库中没有寄存器时,这就不起作用了。我必须手动重新刷新pade,使其显示“你什么都没有!”!“。有没有更好的方法?不重新刷新页面?这是一个全双工。提前谢谢 Python: from flask imp
from flask import Flask, render_template
from flask_socketio import SocketIO, emit, send
from flask_cors import CORS
import MySQLdb
app = Flask(__name__)
app.config['SECRET_KEY'] = 'secret!'
socketio = SocketIO(app)
CORS(app)
@socketio.on('connect')
def con():
handle_message()
def handle_message():
db = MySQLdb.connect("localhost","root","","sitandorder" )
cursor = db.cursor()
cursor.execute("SELECT * FROM historico_pedido")
data = cursor.fetchall()
print(len(data))
if len(data) >= 1:
emit ("test" ,"You have something!")
else:
emit ("test" ,"You have nothing!")
db.close()
if __name__ == '__main__':
socketio.run(app, debug=True, host='127.0.0.1', port=5000 )
Javascript:
<!DOCTYPE html>
<html lang="en" dir="ltr">
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/socket.io/2.0.4/socket.io.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.js">
</script>
<meta charset="utf-8">
<title></title>
</head>
<body>
<script type="text/javascript">
$(document).ready(function(){
var socket = io.connect('http://127.0.0.1:5000');
socket.on('connect', function(){
console.log("Connected"); // Make the connection!
});
socket.on('test', function(arg){
console.log(arg); //Here i show what i get from the handle_message() of python
})
});
</script>
</body>
</html>
$(文档).ready(函数(){
var socket=io.connect('http://127.0.0.1:5000');
socket.on('connect',function(){
console.log(“已连接”);//建立连接!
});
socket.on('test',函数(arg){
console.log(arg);//这里我展示了从python的handle_message()中获得的内容
})
});
在循环中的单独线程中执行处理\u消息
,并将数据发送到客户端可能是一种选择
这是一个基本的想法。看看
@socketio.on('connect')
def con():
thread = Thread(target=background_task)
thread.start()
def background_task():
while True:
time.sleep(1)
handle_message()
def handle_message():
db = MySQLdb.connect("localhost","root","","sitandorder" )
cursor = db.cursor()
cursor.execute("SELECT * FROM historico_pedido")
data = cursor.fetchall()
print(len(data))
if len(data) >= 1:
emit ("test" ,"You have something!")
else:
emit ("test" ,"You have nothing!")
db.close()