Github中的操作

怎么了，为什么我会出错

错误：进程已完成，退出代码为123

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它可能是

xargs

返回123，因为grep返回时带有退出代码1-125。如果任何命令返回非零退出代码，GitHub操作将停止执行脚本

xargs手册页：

xargs以以下状态退出：
[…]
123如果任何命令调用以状态1-125退出

//# This is a basic workflow to help you get started with Actions

name: CI

//# Controls when the action will run. Triggers the workflow on push or pull request
//# events but only for the main branch

on:

  pull_request:

    branches:
      - "**"
    paths:
     - '**.js'        
//# A workflow run is made up of one or more jobs that can run sequentially or in parallel

jobs:

  build:

    //# The type of runner that the job will run on

    runs-on: ubuntu-latest

    //# Steps represent a sequence of tasks that will be executed as part of the job

    steps:

      //# Runs a single command using the runners shell

      - name: Check for Debugger string in js files
        run: |
          find . -type f -print0 | xargs -0 grep -l "Debugger" > answer.txt
          filesize=$(stat -c%s answer.txt)
          if (( filesize > 0 )); then
             exit 1
          else
             exit 0            
          fi