Gps LPC1769 UART读取出错

我有一个GPS模块连接到LPC1769。当我的软件读取它们时，它们经常会像这样乱七八糟：

[gps] Parsing: GPGGA,021447.80$GPGGA,021448.800,,,,,0,0,,,M,,M,,*4B
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPGSV,1,1,00*79
[gps] Parsing: GPRMC,021448.800,V,,,,,0.00,0.00,060180,,,N*41
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 231200246:21448, no fix
[gps] Parsing: GPGGA,021449.80$GPGGA,021450.800,,,,,0,0,,,M,,M,,*42
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPRMC,021450.800,V,,,,,0.00,0.00,060180,,,N*48
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 45200246:21450, no fix
[gps] Parsing: GPGGA,021451.80$GPGGA,021452.800,,,,,0,0,,,M,,M,,*40
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPRMC,021452.800,V,,,,,0.00,0.00,060180,,,N*4A
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 135200246:21452, no fix

每个批处理的第一句话以16个字节开始（总是16个字节；我的代码在解析之前会吞下最初的$）。我的代码如下所示：

[gps] Parsing: GPGGA,021447.80$GPGGA,021448.800,,,,,0,0,,,M,,M,,*4B
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPGSV,1,1,00*79
[gps] Parsing: GPRMC,021448.800,V,,,,,0.00,0.00,060180,,,N*41
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 231200246:21448, no fix
[gps] Parsing: GPGGA,021449.80$GPGGA,021450.800,,,,,0,0,,,M,,M,,*42
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPRMC,021450.800,V,,,,,0.00,0.00,060180,,,N*48
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 45200246:21450, no fix
[gps] Parsing: GPGGA,021451.80$GPGGA,021452.800,,,,,0,0,,,M,,M,,*40
[gps] Parsing: GPGSA,A,1,,,,,,,,,,,,,,,*1E
[gps] Parsing: GPRMC,021452.800,V,,,,,0.00,0.00,060180,,,N*4A
[gps] Parsing: GPVTG,0.00,T,,M,0.00,N,0.00,K,N*32
[gps] GPS location: 135200246:21452, no fix

void gps\u任务（void）{
字符缓冲区[128]，*ptr；
邮包地址；
对于（；；）{
而（Uart_ReadChar（3）！=“$”）；
ptr=缓冲区；
而（（*ptr++=Uart_ReadChar（3））！='\n'）；
*（ptr-1）=0；
日志调试（“解析：%s”，缓冲区）；
//解析缓冲区
Zeptos_睡眠（1000）；
}
}

如果我取消睡眠，问题只会在第一次更新时发生，然后所有其他的都会正常阅读。以下是ReadChar代码：

char-Uart\u-ReadChar（int-uartn）{
LPC_UART_TypeDef*UART=uarts[uartn]；
uint32_t状态；
而（（状态=uart->LSR）&1）==0）{
if（状态和（1 RBR和0xff；
}

当相应的UART IRQ触发时，

BlockOnIrq

调用there返回。我检查是否存在溢出，但没有发生。需要注意的要点：

• UART FIFO恰好也是16字节
• 更新频率为1Hz，

  021447

  etc是时间戳，因此可以看到其他所有更新都在被完全读取，中间的更新在某处丢失

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似乎只有在接收缓冲区为空时才检查溢出。 在读取RBR寄存器之前，尝试检查循环后的溢出