Groovy 查找和修改集合中的重复项

我需要查找和修改集合中的重复条目

我可以做以下工作，这很有效，但需要几个步骤

是否有一种更干净的方法来实现最终输出，指示所有具有重复项的条目

void "test find and mark duplicate entries"() {
    given:
    def sports = ["baseball", "basketball", "football", "basketball", "basketball", "football", "soccer", "volleyball"]

    when:
    def duplicateEntries = sports.findAll { sports.count(it) > 1 }.unique()

    then:
    duplicateEntries == ["basketball", "football"]

    when:
    sports = sports.collect {
        if (duplicateEntries.contains(it)) {
            return it + "-dupe"
        } else {
            return it
        }
    }

    then:
    sports == ["baseball", "basketball-dupe", "football-dupe", "basketball-dupe", "basketball-dupe", "football-dupe", "soccer", "volleyball"]
}

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下面的代码可能会稍微短一点，但我不希望在这里出现奇迹；）

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从@Opal扩展答案。这一个使用groupBy

def sports = ["baseball", "basketball", "football", "basketball", "basketball", "football", "soccer", "volleyball"]
def groupBy=sports.groupBy ().collect { it.value.size()>1  ? "$it.key-dupe" : "$it.key" }
println( groupBy)

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与其他答案一样复杂，只是内存效率更高；-）

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检查或这是否有帮助。不起作用：最后一个断言将失败。你失去了顺序，最终列表的大小与预期列表的大小不一样。这是简洁明了的（好的，在阅读相关文档后请直截了当）。必须是公认的答案。太棒了，谢谢！我不得不稍微修改它以使测试通过，因为collect不会修改原始集合，但这比我所做的要简单得多

sports=sports.collect{sports.count（it）>1？“$it dupe”：it}

def sports = ["baseball", "basketball", "football", "basketball", "basketball", "football", "soccer", "volleyball"]
def groupBy=sports.groupBy ().collect { it.value.size()>1  ? "$it.key-dupe" : "$it.key" }
println( groupBy)

def sports = ["baseball", "basketball", "football", "basketball", "basketball", "football", "soccer", "volleyball"]
sports.collect { sports.count(it) > 1  ? "$it-dupe" : it }