Hadoop 如何获取配置单元中所有可能的模式

我有以下表格：

+----------+----+
|customerID|name|
+----------+----+
|         1| Ram|
+----------+----+

我希望输出为（列值的所有可能值）：

---

拆分字符串、分解数组并使用自身交叉连接来查找所有可能的组合：

 with s as (select col 
              from (select explode( split(lower('Ram'),'')) as col)s 
             where col <>''
           ) 
 select concat(upper(s1.col), s2.col, s3.col) as name, 
        row_number() over() as customerId
   from s s1 
        cross join s s2 
        cross join s s3
where s1.col<>s2.col and s2.col<>s3.col;

如果没有last

，其中s1.cols2.col和s2.cols3.col

您将获得所有组合，如

Aaa

，

Arr

，

Rrr

等

 with s as (select col 
              from (select explode( split(lower('Ram'),'')) as col)s 
             where col <>''
           ) 
 select concat(upper(s1.col), s2.col, s3.col) as name, 
        row_number() over() as customerId
   from s s1 
        cross join s s2 
        cross join s s3
where s1.col<>s2.col and s2.col<>s3.col;

OK
name    customerid
Mam     1
Mar     2
Mrm     3
Mra     4
Ama     5
Amr     6
Arm     7
Ara     8
Rma     9
Rmr     10
Ram     11
Rar     12
Time taken: 185.638 seconds, Fetched: 12 row(s)