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Hive 将配置单元中的字符串转换为日期_Hive_Hiveql - Fatal编程技术网

Hive 将配置单元中的字符串转换为日期

Hive 将配置单元中的字符串转换为日期,hive,hiveql,Hive,Hiveql,我在hive中有这个日期格式:20180618151752 执行以下查询以按以下方式保留它: select concat(substr(xdr.time_stop,1,8),' ', substr(xdr.time_stop,9,2),':', substr(xdr.time_stop,10,2),':', substr(xdr.time_stop,11,2)) as date from padl.fraude_vozm_xdr; 20180618 18:17:52 现在,我需要将该字符串字段

我在hive中有这个日期格式:20180618151752

执行以下查询以按以下方式保留它:

select
concat(substr(xdr.time_stop,1,8),' ',
substr(xdr.time_stop,9,2),':',
substr(xdr.time_stop,10,2),':',
substr(xdr.time_stop,11,2)) as date
from padl.fraude_vozm_xdr;
20180618 18:17:52

现在,我需要将该字符串字段转换为日期,我该怎么做


谢谢

使用来自unixtime的
unix\u时间戳

from_unixtime(unix_timestamp('20180618151752','yyyyMMddHHmmss'),'yyyyMMdd HH:mm:ss')