XML到HTML的XSLT_Html_Xml_Xslt - Fatal编程技术网

XML到HTML的XSLT

html xml xslt

XML到HTML的XSLT,html,xml,xslt,Html,Xml,Xslt,您好，我正在寻找用于生成HTML的XSLT，如下所示。以下是转换的详细信息。请提供你的意见 In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li>

您好，我正在寻找用于生成HTML的XSLT，如下所示。以下是转换的详细信息。请提供你的意见

In HTML an Li element should be populated.

    <li>
        <a>Test</a>
    </li>

And under each Pagegroup for every Page Ul should be populated.
<ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
</ul>

对于每个页面组，我需要创建一个

In HTML an Li element should be populated.

    <li>
        <a>Test</a>
    </li>

And under each Pagegroup for every Page Ul should be populated.
<ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
</ul>

在HTML中，应填充Li元素。

试验

每个页面的每个页面组下都应填充Ul。


测试角色1


测试角色2

XML:

In HTML an Li element should be populated.

    <li>
        <a>Test</a>
    </li>

And under each Pagegroup for every Page Ul should be populated.
<ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
</ul>

输出HTML预期值

In HTML an Li element should be populated.

    <li>
        <a>Test</a>
    </li>

And under each Pagegroup for every Page Ul should be populated.
<ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
</ul>

<ul>
    <li>
        <a>Test</a>
    </li>
    <ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
        <ul>
            <li>
                <a>Projects</a>
            </li>
            <ul>
                <li>
                    <a>Test 2 3</a>
                </li>
                <li>
                    <a>Test 2 5</a>
                </li>
            </ul>
        </ul>
    </ul>
</ul>



试验



测试角色1


测试角色2



项目



测试2 3


测试2 5

XSLT已尝试

In HTML an Li element should be populated.

    <li>
        <a>Test</a>
    </li>

And under each Pagegroup for every Page Ul should be populated.
<ul>
        <li>
            <a>Test Role 1</a>
        </li>
        <li>
            <a>Test Role 2</a>
        </li>
</ul>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
            <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
            <xsl:template match="pagegroup">
                        <ul>
                                    <xsl:apply-templates select="pages"/>
                                    <li>
                                    <xsl:value-of select="@title"/>
                                    </li>
                        </ul>
            </xsl:template>
            <xsl:template match="pages">
                        <li>
                                    <xsl:value-of select="@role"/>
                                    <xsl:if test="pagegroup">
                                                <ul>
                                                            <xsl:apply-templates select="pages"/>
                                                            <li>
                                                            <xsl:value-of select="@title" />
                                                            </li>
                                                </ul>
                                    </xsl:if>
                        </li>
            </xsl:template>
</xsl:stylesheet>

你离得不远。主要问题是，在要匹配页面组的模板中，您正在这样做

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>

<xsl:apply-templates select="pages"/>

如果确实要这样做，请同时匹配页面和页面组

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>

<xsl:apply-templates/>

尝试以下XSLT

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="pagegroup"> <ul> <li> <xsl:value-of select="@title"/> </li> <ul> <xsl:apply-templates/> </ul> </ul> </xsl:template> <xsl:template match="pages"> <li> <xsl:value-of select="@role"/> </li> </xsl:template> </xsl:stylesheet>

应用于XML时，将输出以下内容

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>

<ul> <li>Test</li> <ul> <li>Test Role 1</li> <li>Test Role 2</li> <ul> <li>Projects</li> <ul> <li>Rol 3</li> <li>Rol 4</li> </ul> </ul> </ul> </ul>

试验测试角色1 测试角色2 计划 Rol 3 Rol 4
我想你有点不明白你想要什么

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>
这一点越来越接近了，但您仍然无法得到您想要的，因为在一堆页面中，您似乎想要角色，在另一个描述中。这是可能的，但我不确定这是否是你想要的

In HTML an Li element should be populated. <li> <a>Test</a> </li> And under each Pagegroup for every Page Ul should be populated. <ul> <li> <a>Test Role 1</a> </li> <li> <a>Test Role 2</a> </li> </ul>

<?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="pagegroup"> <ul> <li> <a><xsl:value-of select="@title"/></a> </li> <xsl:if test="pages | pagegroup"> <ul> <xsl:apply-templates select="pages | pagegroup"/> </ul> </xsl:if> </ul> </xsl:template> <xsl:template match="pages"> <li> <a><xsl:value-of select="@role"/></a> <xsl:if test="pagegroup"> <ul> <li> <xsl:value-of select="@title" /> </li> </ul> </xsl:if> </li> </xsl:template> </xsl:stylesheet>

根据您的结构，您需要一个递归模板，该模板将遍历所有页面组以创建LIs。您的实际输出是什么？