If statement 我想回到这个问题,如果用户写的不是“quot;是”&引用;否";在我的代码中使用if/else
我想回到问题,如果用户在我的代码中用if/else写“是”“否”以外的词 你只回答“是”或“不是”,但像“sjfkhs”这样的回答让我很难过。如果有人写得像“sdjk”,我想重复这个问题If statement 我想回到这个问题,如果用户写的不是“quot;是”&引用;否";在我的代码中使用if/else,if-statement,kotlin,If Statement,Kotlin,我想回到问题,如果用户在我的代码中用if/else写“是”“否”以外的词 你只回答“是”或“不是”,但像“sjfkhs”这样的回答让我很难过。如果有人写得像“sdjk”,我想重复这个问题 fun main(args: Array<String>) { var CanI_Play: String var IfUrMotherDisturb: String var HaveYouFreeTime: String var Question1 = "Can I pl
fun main(args: Array<String>) {
var CanI_Play: String
var IfUrMotherDisturb: String
var HaveYouFreeTime: String
var Question1 = "Can I play?"
println(Question1)
CanI_Play = readLine()!!.toUpperCase() //wstawienie !!. mówi komputerowi , że nie wprowadzimy null
// czyli chyba pustego pola które w tym przypadku bedzie zmienione z małych liter na duże
if (CanI_Play=="YES") {
println("So you can play from now")
}
if (CanI_Play=="NO") {
println("You can't play yet...:(")
println("Have You free time?")
HaveYouFreeTime = readLine()!!.toUpperCase()
if (HaveYouFreeTime=="NO") {
println("Do what You should do and You can play")
}
if (HaveYouFreeTime=="YES") {
println("If Your mother disturb?")
IfUrMotherDisturb = readLine()!!.toUpperCase()
if (IfUrMotherDisturb=="YES"){
println("Bad news. Time to look for new house. OMFG")
}
if (IfUrMotherDisturb=="NO"){
println("Great news! You can play!")
}
else{
println("I Want to return to question IfUrMotherDisturb")
}
}
else{
println("I want to return to question HaveYouFreeTime")
}
}
else{
println("I want to return to question CanI_Play")
}
}
fun main(args:Array){
var CanI_Play:弦乐
变量ifurMotherDistrict:字符串
var HaveYouFreeTime:String
var Question1=“我可以玩吗?”
println(问题1)
CanI_Play=readLine()!!.toUpperCase()//wstavienie!!.mówi komputerowi,że wprowadzimy null
//czyli chyba pustego pola które w tym przypadku bedzie zmienione z małych l na duże
如果(CanI_播放=“是”){
println(“这样你就可以从现在开始玩了”)
}
如果(CanI_播放=“否”){
println(“你还不能玩…:(”)
println(“你有空吗?”)
HaveYouFreeTime=readLine()!!.toUpperCase()
如果(HaveYouFreeTime==“否”){
println(“做你应该做的,你可以玩”)
}
如果(HaveYouFreeTime==“是”){
println(“如果你妈妈打扰了?”)
IfurMotherDistribut=readLine()!!.toUpperCase()
如果(IfurMotherDistribut==“是”){
println(“坏消息。该找新房子了。OMFG”)
}
如果(IfurMotherDistribut==“否”){
println(“好消息!你可以玩了!”)
}
否则{
println(“我想回到问题ifurmotherdistrip”)
}
}
否则{
println(“我想回到问题HaveYouFreeTime”)
}
}
否则{
println(“我想回到问题CanI_Play”)
}
}
在一般情况下,仅使用if/else是不可能的。一个选项是使用循环,而另一个选项是使用递归。我将演示如何同时使用这两种方法。我稍微更改了您的代码,以匹配标准Kotlin命名约定和样式。如果您使用某种类,并且需要遵循特定的对于该类,忽略我的更改。以下是更改的问题代码:
fun main() {
println("Can I play?")
val canIPlay = readLine()!!.toUpperCase()
if (canIPlay == "YES") {
println("So you can play from now")
}
if (canIPlay == "NO") {
println("You can't play yet...:(")
println("Have You free time?")
val haveYouFreeTime = readLine()!!.toUpperCase()
if (haveYouFreeTime == "NO") {
println("Do what You should do and You can play")
}
if (haveYouFreeTime == "YES") {
println("If Your mother disturb?")
val ifUrMotherDisturb = readLine()!!.toUpperCase()
if (ifUrMotherDisturb == "YES") {
println("Bad news. Time to look for new house. OMFG")
}
if (ifUrMotherDisturb == "NO") {
println("Great news! You can play!")
} else {
println("I Want to return to question IfUrMotherDisturb")
}
} else {
println("I want to return to question HaveYouFreeTime")
}
} else {
println("I want to return to question CanI_Play")
}
}
下面是如何使用递归解决此问题:
fun main() {
askIfCanPlay()
}
fun askIfCanPlay() {
println("Can I play?")
val canIPlay = readLine()!!.toUpperCase()
if (canIPlay == "YES") {
println("So you can play from now")
}
if (canIPlay == "NO") {
askIfFreeTime()
} else {
askIfCanPlay()
}
}
fun askIfFreeTime() {
println("You can't play yet...:(")
println("Have You free time?")
val haveYouFreeTime = readLine()!!.toUpperCase()
if (haveYouFreeTime == "NO") {
println("Do what You should do and You can play")
}
if (haveYouFreeTime == "YES") {
askIfMotherDisturb()
} else {
askIfFreeTime()
}
}
fun askIfMotherDisturb() {
println("If Your mother disturb?")
val ifUrMotherDisturb = readLine()!!.toUpperCase()
if (ifUrMotherDisturb == "YES") {
println("Bad news. Time to look for new house. OMFG")
}
if (ifUrMotherDisturb == "NO") {
println("Great news! You can play!")
} else {
askIfMotherDisturb()
}
}
下面是如何使用while循环解决此问题:
fun main() {
var canIPlay = ""
while(!(canIPlay == "YES" || canIPlay == "NO")){
println("Can I play?")
canIPlay = readLine()!!.toUpperCase()
}
if (canIPlay == "YES") {
println("So you can play from now")
}
else if (canIPlay == "NO") {
println("You can't play yet...:(")
var haveYouFreeTime = ""
while(!(haveYouFreeTime == "YES" || haveYouFreeTime == "NO")){
println("Have You free time?")
haveYouFreeTime = readLine()!!.toUpperCase()
}
if (haveYouFreeTime == "NO") {
println("Do what You should do and You can play")
}
if (haveYouFreeTime == "YES") {
var ifUrMotherDisturb = ""
while(!(ifUrMotherDisturb == "YES" || haveYouFreeTime == "NO")){
println("If Your mother disturb?")
ifUrMotherDisturb = readLine()!!.toUpperCase()
}
if (ifUrMotherDisturb == "YES") {
println("Bad news. Time to look for new house. OMFG")
}
if (ifUrMotherDisturb == "NO") {
println("Great news! You can play!")
} else {
assert(false)// this will never happen
}
} else {
assert(false)// this will never happen
}
}else {
assert(false)//this will never happen
}
}
我个人更喜欢递归方法,特别是因为kotlin的目标是成为一种功能性更强的语言。Offtopic:when:为了防止由于太深的递归而导致堆栈溢出,kotlin还提供了
tailrec
,请参阅Agreed。但是我没有提到tailrec或递归防护,因为s似乎是一个初学者问题,不想让事情变得过于复杂。tailrec
修饰符使Kotlin中的递归比Java中的递归“更具功能”,事实上,编译器会将您的第一个解决方案转换为两个do…而循环,如果您将它们标记为tailrec
,那么没有它第二种方法似乎更好。