如何使用swift在iOS中添加特殊字符？ 我想给iOS一个新的数据，我想把一些数据发送到服务器，但是我不能发送莫比尔号码 >代码> + 91 和血型 >代码> A+ ..它被发送到FiasBase +被替换为空间 >“ >此代码>（91）和（a）< /代码>

功能转换器参数

  func convertToParameters(_ params: [String: AnyObject?]) -> String {
        var paramList: [String] = []

        for (key, value) in params {
            guard let value = value else {
                continue
            }
           let scapedKey = key
           let scapedValue = value
            print("employee add status objects   =   ","\(scapedKey)=\(scapedValue as AnyObject)")
            paramList.append("\(scapedKey)=\(scapedValue as AnyObject)")
        }
        return paramList.joined(separator: "&")
    }

Json错误：

resultjson=two   :  {
    error =     {
        code = "auth/invalid-phone-number";
        message = "The phone number must be a non-empty E.164 standard compliant identifier string.";
    };
    success = 0;
}

firebase控制台中出现错误：

resultjson=two   :  {
    error =     {
        code = "auth/invalid-phone-number";
        message = "The phone number must be a non-empty E.164 standard compliant identifier string.";
    };
    success = 0;
}

---

您的实际问题是您的参数没有得到正确的url编码

代码的临时解决方案：

在

convertToParams

方法中，进行以下更改：

let scapedKeyEncoded =  scapedKey.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed);
let scapedValueEncoded =  scapedValue.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed);
paramList.append("\(scapedKeyEncoded)=\(scapedValueEncoded)"

注意：您的scapedValue必须是String，因此，将employeeDetails设置为[String:String]

永久解决方案（编码查询参数的完美方式）：

resultjson=two   :  {
    error =     {
        code = "auth/invalid-phone-number";
        message = "The phone number must be a non-empty E.164 standard compliant identifier string.";
    };
    success = 0;
}

为此，您可以将代码更改为以下内容：

删除

convertToParameters

方法

添加以下方法来代替它

class func getURLRequestWith(urlStr:String, paramsDict:[String:String]?, isParamsAsQuery:Bool, isParamsAsBody:Bool) -> URLRequest? {

guard var components = URLComponents(string: urlStr) else { return nil }

if paramsDict != nil{
    components.queryItems = paramsDict!.map({ (key, value) -> URLQueryItem in
        return URLQueryItem(name: key, value: value)
    })
}

if isParamsAsQuery{
    let request = URLRequest(url: components.url!);
    return request;
}

if isParamsAsBody{
    let url = URL(string: urlStr);
    var request = URLRequest(url: url!);

    let bodyStr = components.percentEncodedQuery;
    if bodyStr != nil{
        request.httpBody = bodyStr!.data(using: String.Encoding.utf8);
    }
    return request;
}

let url = URL(string: urlStr);
let request = URLRequest(url: url!);
return request;
}

从代码中删除以下行：

let convertedvalue : String = convertToParameters(employeeDetails)

print("convertedvalues :   \(convertedvalue)")


let myUrl = URL(string: "https://us-central1-pickceltest.cloudfunctions.net/rebliss/createNewUser");

var request = URLRequest(url:myUrl!)
request.httpBody = postString.data(using: String.Encoding.utf8);

添加以下代码，而不是上面删除的代码

let urlStr = "https://us-central1-pickceltest.cloudfunctions.net/rebliss/createNewUser"

var request = getURLRequestWith(urlStr: urlStr, paramsDict: employeeDetails, isParamsAsQuery: false, isParamsAsBody: true)

将

employeeDetails

字典转换为类型

[String:String]

，而不是

[String:AnyObject]

---

现在，试试你的代码，它肯定会工作。

请检查下面的解决方案是否有效。向url添加百分比编码

// Create NSURL Ibject
let url : NSString = urlWithParams as NSString

let urlStr = url.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed)

let searchURL : NSURL = NSURL(string: urlStr! as String)!

// Creaste URL Request
let request = NSMutableURLRequest(url: searchURL as URL, cachePolicy: NSURLRequest.CachePolicy.reloadIgnoringCacheData, timeoutInterval: 120)

// Set request HTTP method to GET. It could be POST as well
request.httpMethod = "POST"

---

您需要显式地对

+

符号进行百分比编码，否则它会被解释为一个空格–您可以阅读更多关于它的内容（扰流板：它不进行百分比编码）@holex您可以建议一些如何解决此问题的参考链接吗。。。可能会有帮助。评论不用于长时间讨论；这段对话已经结束。