Ios 未调用XMPPFramework发送元素方法

你好，我正在用XMPPFramework制作一个聊天应用程序

我已通过引用以下链接在我的项目中设置了XMPPFramework：-

发送消息的代码：-

    NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
    [body setStringValue:messageStr];

    NSXMLElement *message = [NSXMLElement elementWithName:@"message"];
    [message addAttributeWithName:@"type" stringValue:@"chat"];
    [message addAttributeWithName:@"to" stringValue:fnjid];
    [message addChild:body];
    [self.xmppStream sendElement:message];

此代码工作正常，但现在无法工作…方法“发送元素””未调用。它位于xmppstream类中

- (void)sendElement:(NSXMLElement *)element

---

此方法在连接到服务器时调用，但不仅在发送消息时起作用

可能是复合和授权有问题

- (void)xmppStreamDidConnect:(XMPPStream *)sender
{
    isXmppConnected = YES;
    NSError *error = nil;
    if (![[self xmppStream] authenticateWithPassword:password error:&error])
    {

    }
}

And

- (void)xmppStreamDidAuthenticate:(XMPPStream *)sender
{
    XMPPPresence *presence = [XMPPPresence presenceWithType:@"available"];
    [[self xmppStream] sendElement:presence];
}


In this case, the method does not work correctly , because state != STATE_XMPP_CONNECTED

- (void)sendElement:(NSXMLElement *)element
{
 if (element == nil) return;

 dispatch_block_t block = ^{ @autoreleasepool {

  if (state == STATE_XMPP_CONNECTED)
  {
   [self sendElement:element withTag:TAG_XMPP_WRITE_STREAM];
  }
  else
  {
   [self failToSendElement:element];
  }
 }};

 if (dispatch_get_specific(xmppQueueTag))
  block();
 else
  dispatch_async(xmppQueue, block);
}

---

当未调用

sendElement:

时，

self.xmppStream

nil？