Ios 数据无法’；因为它是’；t格式正确。斯威夫特5

我正在试着从中解码数据。我得到了正确的json，响应代码为200，但解码器无法读取数据，因为格式不正确。我尝试了很多不同的方法。我正在尝试获取有关人类的信息

这是我的密码：

模型文件

struct people: Codable {
    let count: Int
    let next: String?
    let previous: String?
    let results: [result]
}

struct result: Codable{
    let name: String
    let height: Int
    let mass: Int
    let hair_color: String
    let skin_color: String
    let eye_color: String
    let birth_year: String
    let gender: String
    let homeworld: String
    let films: [String]
    let species: [String]
    let vehicles: [String]
    let starships: [String]
    let created: String
    let edited: String
    let url: String
    
}

struct APIError: Codable {
    let detail: String
}

网络服务

typealias OnApiSucces = (people) -> Void
typealias OnApiError = (String) -> Void

struct ApiService {
    static let shared = ApiService()
    
    let URL_BASE = "https://swapi.dev/api"
    let URL_PEOPLE = "/people"
    
    let session = URLSession(configuration: .default)
    

    
    func getResults(onSuccess: @escaping OnApiSucces, onError: @escaping OnApiError) {

        let url = URL(string: "\(URL_BASE)\(URL_PEOPLE)")!
        var request = URLRequest(url: url)
        request.httpMethod = "GET" // GET, PUT, POST, DELETE for some different api
        request.setValue("application/json", forHTTPHeaderField: "Content-Type")

        let task = session.dataTask(with: request) { (data, response, error) in

                if let error = error {
                    onError(error.localizedDescription)
                    return
                }

                guard let data = data, let response = response as? HTTPURLResponse else {
                    onError("Invalid data or response")
                    return
                }

                do{
                    if response.statusCode == 200 {
                        print("Code is \(response.statusCode)")
                        let results = try JSONDecoder().decode(people.self, from: data)
                        onSuccess(results)
                    } else {
                        let err = try JSONDecoder().decode(APIError.self, from: data)
                        print("Code is \(response.statusCode)")
                        onError(err.detail)
                    }
                }
                catch {
                    onError(error.localizedDescription)
                }

            }
        task.resume()

        }

    }

**获取ViewController上的数据**

    func getResults() {
        ApiService.shared.getResults { (people) in
            self.results = people.results
        } onError: { (error) in
            debugPrint(error.description)
        }
    }

---

首先，您的数据无法读取，因为在星球大战API中，

height

和

mass

表示为

String

，而在

Codable

结构中则表示为

Int

另外，尝试将

CodingKeys

添加到

Codable

结构中，使结构遵守命名约定（特别是关于

属性的颜色

变体），例如

---

提示：将生成的JSON粘贴到中，以获得生成的模型结构，而不是打印

错误。localizedDescription

在

JSONDecoder

catch块中，错误消息毫无意义。打印

错误

，它会显示真正可理解的错误。在JSON中，用双引号括起来的所有内容都是

字符串

偶数

“123”

或

“false”

。谢谢！我改成了字符串，现在可以使用了。或者，如果映射像这样简单，可以使用

JSONDecoder.KeyDecodingStrategy.convertFromSnakeCase

。将类型更改为字符串。

struct result: Codable{
    let name: String
    let height: String
    let mass: String
    let hairColor: String  // changed from hair_color
    let skinColor: String
    let eyeColor: String
    let birthYear: String
    let gender: String
    let homeworld: String
    let films: [String]
    let species: [String]
    let vehicles: [String]
    let starships: [String]
    let created: String
    let edited: String
    let url: String
    enums CodingKeys: String, CodingKey {
      case name = "name"
      case height = "height"
      case mass = "mass"
      case hairColor = "hair_color"
      case skinColor = "skin_color"
      case eyeColor = "eye_color"
      case birthYear = "birth_year"
      case gender = "gender"
      case homeworld = "homeworld"
      case films = "films"
      case species = "species"
      case vehicles = "vehicles"
      case starships = "starships"
      case created = "created"
      case edited = "edited"
      case url = "url" 
    }
}