Ios 国家统计局字典；难以获得价值观

这是我用于词典的JSON文件：

{

    "Reports": {
        "Title of sheet": {
            "id": "1",
            "active": "0",
            "title": "Title of sheet",
            "date": "October 22, 2012",
            "description": "description",
            "ext": "DOCX",
            "fortest": "Tuesday, October 23",
            "subject": "Budget",
            "author": "xxxxxxxxxx",
            "email": "xxxxx@gmail.com"
        }
    }
}

这是我用来将其转换为字典的代码（在我请求之后）

这将生成以下内容的输出：

(
        {
        key = Reports;
        value =         {
            "Sheet Title" =             {
                    active = 0;
                    author = "xxx xxxxxx";
                    date = "October 22, 2012";
                    description = "Description";
                    dl = "9 downloads";
                    email = "xxxxxxx@gmail.com";
                    ext = DOCX;
                    fortest= "Tuesday, October 23";
                    id = 1;
                    subject = Budget;
                    title = "Sheet title";
            };
        };
    }
)

这是我的问题。。。如何将“工作表标题”更改为info=就像我对报告（键）和值所做的那样？reports数组将包含更多的条目，所有条目的旁边都有不同的“工作表标题”数组。我不想具体地按名称调用数组，因为总会有数组添加到我的json中。请帮忙，谢谢

另外，我试过摆弄for循环，但没有用

---

编辑：我想要这样的东西：

(
        {
        key = Reports;
        value =         {
            info =             {
                active = 0;
                author = "xxx xxxxxx";
                date = "October 22, 2012";
                description = "Description";
                dl = "9 downloads";
                email = "xxxxxxx@gmail.com";
                ext = DOCX;
                fortest = "Tuesday, October 23";
                id = 1;
                subject = Budget;
                title = "Sheet title";
            };
        };
    }
)

---

编辑2：

---

明白了！我最终通过一个相当有创意的解决方案找到了答案。我基本上将我的NSDictionary转换为NSArray，并在两者之间切换，如果这有意义的话。。。回家后我会发布一些代码

根据我对您问题的理解，添加

子目录=[NSDictionary Dictionary WithObject:[Subdct valueForKey:[[Subdct allKeys]objectAtIndex:0]]forKey:@“info”]到方法。只需将其添加到行
NSDictionary*subct=[object valueForKey:key]之后

例如：-

 self.tableDataSource = [NSMutableArray array];

 for (NSString *key in object.allKeys) // object is your root NSDictionary
    {
        NSDictionary *subDict = [object valueForKey:key];
        subDict = [NSDictionary dictionaryWithObject:[subDict valueForKey:[[subDict allKeys] objectAtIndex:0]] forKey:@"info"];
        //create a new dictionary with two values - one for the key and one for the value.
        NSMutableDictionary *newDict = [NSMutableDictionary dictionary];
        [newDict setValue:subDict forKey:@"value"];
        [newDict setValue:key forKey:@"key"];
        [self.tableDataSource addObject:newDict];
    }

应该打印出来

(
        {
        key = Reports;
        value =         {
            info =             {
                active = 0;
                author = "xxx xxxxxx";
                date = "October 22, 2012";
                description = "Description";
                dl = "9 downloads";
                email = "xxxxxxx@gmail.com";
                ext = DOCX;
                fortest = "Tuesday, October 23";
                id = 1;
                subject = Budget;
                title = "Sheet title";
            };
        };
    }
)

更新：
根据下面的注释，您需要使用
subct=[NSDictionary dictionaryWithObject:[subct valueForKey:[[subct allKeys]objectAtIndex:i]]forKey:@“info”]以获取所有子阵列。根据您的要求修改此行
 你不使用的原因是什么？@AJak我是为请求做的，但不是为了这个…@user1789040，所以基本上你需要的是
subct=[NSDictionary dictionary dictionaryWithObject:[subct valueForKey:[[subct allKeys]objectAtIndex:0]]forKey:@“Info]。只需将其添加到行
NSDictionary*subct=[object valueForKey:key]之后
(
        {
        key = Reports;
        value =         {
            info =             {
                active = 0;
                author = "xxx xxxxxx";
                date = "October 22, 2012";
                description = "Description";
                dl = "9 downloads";
                email = "xxxxxxx@gmail.com";
                ext = DOCX;
                fortest = "Tuesday, October 23";
                id = 1;
                subject = Budget;
                title = "Sheet title";
            };
        };
    }
)