Ios 按钮未运行Xcode

我在视图控制器中有此代码，但拨号按钮未运行，图像视图未显示任何内容

    //
//  ViewController.m
//  EasyBuy
//
//  Created by Moments on 9/2/15.
//  Copyright (c) 2015 Moments. All rights reserved.
//

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

- (void)viewDidLoad {
    [super viewDidLoad];
    imageview.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:@" http://93.95.207.34/easybuy.com/car/car2.png "]]];

    // Do any additional setup after loading the view, typically from a nib.
}
- (IBAction)callus:(id)sender {

    [[ UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:00962796880853"]];
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

@end

---

您能帮我一下吗？

在您的情况下，字符串中有空格，不能将字符串转换为url

@”http://93.95.207.34/easybuy.com/car/car2.png “

所以这个形象实际上并没有被创造出来

对于ImageView，请使用此代码

NSURL *url = [NSURL URLWithString:@"http://93.95.207.34/easybuy.com/car/car2.png"];

NSData *data = [NSData dataWithContentsOfURL:url];
UIImage *image = [UIImage imageWithData:data];

[imageview setImage:image];   

对于调用过程，请使用以下命令

NSString *phoneStr = @"telprompt://00962796880853";
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneStr]];

并确保已将图像视图和uibutton操作附加到interfaceBuilder（storyboard或.xib）

希望对您有所帮助

在真实设备上检查它

[[ UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel://00962796880853"]];

---

对于ImageView，您添加了空白。你应该修剪一下那个空间。另一件事是你应该在编码后调用url。为了顺利加载图像，您应该使用

dispatch\u get\u global\u queue

在后台队列中调用url。检查（）

电话费

NSURL *url = [NSURL URLWithString:[NSString  stringWithFormat:@"telprompt://00962796880853"]];

if ([[UIApplication sharedApplication] canOpenURL:url]) {
    [[UIApplication sharedApplication] openURL:url];
} else
{
    //Call functionality not available.
}

---

这在interfaceBuilder上是正确的？？？？{@interface ViewController:UIViewController{IBOutlet UIImageView*imageview；u弱IBOutlet UIButton*callus；}@end}所以在设备上检查它，而不是在模拟器上调用模拟器不起作用，您的问题将得到解决

NSURL *url = [NSURL URLWithString:[NSString  stringWithFormat:@"telprompt://00962796880853"]];

if ([[UIApplication sharedApplication] canOpenURL:url]) {
    [[UIApplication sharedApplication] openURL:url];
} else
{
    //Call functionality not available.
}