Ios NSMutableDictionary addEntriesFromDictionary未正确合并词典

我有一个JSON响应，存储为NSMutableDictionary，如下所示：

    {
        "list": { "ID1", "ID2", "ID3" },

        "items": {
            "ID1" : { "name" : "shoe" },
            "ID2" : { "name" : "pants" },
            "ID3" : { "name" : "hat" }
        }
    }

我需要让NSMutableDictionary添加来自任何其他JSON响应的条目，因此如果我收到如下新响应：

{
    "list": { "ID4", "ID5", "ID6" },

    "items": {
        "ID4" : { "name" : "shirt" },
        "ID5" : { "name" : "tie" },
        "ID6" : { "name" : "glasses" }
    }
}

    {
        "list": { "ID1", "ID2", "ID3", "ID4", "ID5", "ID6" },

        "items": {
            "ID1" : { "name" : "shoe" },
            "ID2" : { "name" : "pants" },
            "ID3" : { "name" : "hat" },
            "ID4" : { "name" : "shirt" },
            "ID5" : { "name" : "tie" },
            "ID6" : { "name" : "glasses" }
        }
    }

更新的NSMutableDictionary需要如下显示：

{
    "list": { "ID4", "ID5", "ID6" },

    "items": {
        "ID4" : { "name" : "shirt" },
        "ID5" : { "name" : "tie" },
        "ID6" : { "name" : "glasses" }
    }
}

    {
        "list": { "ID1", "ID2", "ID3", "ID4", "ID5", "ID6" },

        "items": {
            "ID1" : { "name" : "shoe" },
            "ID2" : { "name" : "pants" },
            "ID3" : { "name" : "hat" },
            "ID4" : { "name" : "shirt" },
            "ID5" : { "name" : "tie" },
            "ID6" : { "name" : "glasses" }
        }
    }

不幸的是，当我调用带有附加项的

addEntriesFromDictionary

时，我得到以下结果：

{
            "list": { "ID1", "ID2", "ID3" },

            "items": {
                "ID1" : { "name" : "shoe" },
                "ID2" : { "name" : "pants" },
                "ID3" : { "name" : "hat" }
            }
        }
             "list": { "ID4", "ID5", "ID6" },

             "items": {
                 "ID4" : { "name" : "shirt" },
                 "ID5" : { "name" : "tie" },
                 "ID6" : { "name" : "glasses" }
           }
    }

---

假设我们拥有与您示例中相同的词典：

let key1 = "list"
let key2 = "items"

var rec = [key1:["ID1","ID2","ID3"],
           key2:["ID1":["name":"shoe"],"ID2":["name":"pants"],"ID3":["name":"hat"]]] as [String : Any]
let inc = [key1:["ID4","ID5","ID6"],
           key2:["ID4":["name":"shirt"],"ID5":["name":"tie"],"ID6":["name":"glasses"]]] as [String : Any]

我使用以下基本原理来找到解决方案：

。。。在下文中实现了此代码段：

func merge(_ inc:[String:Any], into rec: inout [String:Any]) -> [String:Any] {
    for (_, vals) in inc {
        if var recKeys = rec[key1] as? [String],
            var recItems = rec[key2] as? [String:[String:String]],
            let incItems = inc[key2] as? [String:[String:String]] {

            if let incValIds = vals as? [String] {
                for id in incValIds {
                    if let newVal = incItems[id] {
                        if recKeys.contains(id) {
                            for (newValId, newValObj) in newVal {
                                guard var tab = recItems[id] else { continue }
                                tab[newValId] = newValObj
                                recItems[id] = tab
                            }
                        } else {
                            recKeys.append(id)
                            recItems[id] = newVal
                        }
                    }
                }
            }
            rec[key1] = recKeys
            rec[key2] = recItems
        }
    }
    return rec
}

。。。并使用如下所述的函数来获得以下定义的结果：

let updatedInfo = merge(inc, into: &rec)
print(updatedInfo)

---

您现在可以根据需要正确地合并提供的两个词典。

我认为您需要做的是所谓的“深度合并”，这可能会对您有所帮助：我建议您创建一个类，该类使用适当的初始值设定项和函数来表示数据，以接受字典，而不是直接依赖字典结构