Ios 计数器属性不更改值

我正在Swift游乐场应用程序中进行测验，我想保留正确答案数量的计数器。

correct

的值没有改变，我也不知道为什么

  var correct:Int = 0
    func qa(question: String, answer: String) {
    show(question)
    var ans = ask("answer")
    if (ans.lowercased() == answer) {
        show("correct")
        correct = correct + 1
    } else {
        show("wrong you numpty!")
    }
}
     func qaor(question: String, answer: String, answer2: String) {
    show(question)
    var ans = ask("answer")
    if (ans.lowercased() == answer) || (ans.lowercased() == answer2) {
        show("correct")
        correct = correct + 1
    } else {
        show("wrong you numpty!")
    }
}


show("What is your name?")

let name = ask("Name")

show("Hi " + name)

qa(question: "What is the name of the character played by Simon Jones in the Hitchikers Guide to the Galaxy?", answer: "arthur dent")

qaor(question: "What is voiced by Peter Jones in the Hitchikers Guide to the Galaxy?", answer: "the book", answer2: "the guide")

qa(question: "finish this sentence  .doing the coastlines was always my Favourite, the rough crinkley edges, .... ", answer: "fjords")

var cf = "no"
if (correct == 0) {
    var cf = "no"
} else if (correct == 1) {
    var cf = "one"
} else if (correct == 2) {
    var cf = "two"
} else if (correct == 3) {
    var cf = "three"
}

show("you got " + cf + " questions correct out of three")

---

不要为每个if/else语句声明

cf

变量。它会创建一个局部变量，并且您不会更改第一个

cf

相反，请尝试以下方法：

var cf = "no"
if (correct == 0) {
    cf = "no"
} else if (correct == 1) {
    cf = "one"
} else if (correct == 2) {
    cf = "two"
} else if (correct == 3) {
    cf = "three" 
}

show("you got " + cf + " questions correct out of three")

---

不要在if-else块中重新声明

cf

。只需执行

cf=“no”

等操作。请至少根据一些样式指南对代码进行格式化和缩进。这段代码不可读，不属于StackOverflow。谢谢你，berksy92，我刚刚测试了它，它工作正常