Ios 如何获取联系人ID

Ios 如何获取联系人ID,ios,ios8,ios8.1,addressbookui,Ios,Ios8,Ios8.1,Addressbookui,我无法从通讯簿中获取联系人ID 我的.m文件: -(IBAction)test:(id)sender { ABPeoplePickerNavigationController* picker = [[ABPeoplePickerNavigationController alloc] init]; picker.peoplePickerDelegate = self; [self presentViewController:picker animated:YES compl

我无法从通讯簿中获取联系人ID

我的.m文件:

-(IBAction)test:(id)sender
{
    ABPeoplePickerNavigationController* picker = [[ABPeoplePickerNavigationController alloc] init];
    picker.peoplePickerDelegate = self;
    [self presentViewController:picker animated:YES completion:nil];
}

-(void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person
{
    [peoplePicker dismissViewControllerAnimated:YES completion:nil];
    ABRecordID recordID = ABRecordGetRecordID(person);
    label.text = [NSString stringWithFormat:@"%d", recordID];

}

-(void)peoplePickerNavigationControllerDidCancel:(ABPeoplePickerNavigationController *)peoplePicker
{
    [peoplePicker dismissViewControllerAnimated:YES completion:nil];
}
我将AddressBook和AddressBookUI导入到.h文件中。 一切正常,但我拿错了身份证。 每次我只得到ID-1,这代表错误

希望你能帮助我

非常感谢,
Christian

在iOS 8中,它不再在仅显示人员选取器时自动请求地址簿的权限。(其想法是,仅选取者并不能真正让应用程序访问您的联系人,因此不需要任何权限。当应用程序无法真正获取联系人详细信息时,它提供了低摩擦的用户界面。)

但是,在您的情况下,您实际上是在尝试通过编程检索有关联系人的信息。为此,您确实需要许可。因此,在介绍选取者之前,您可能希望获得地址簿的许可:

ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus();
if ((status == kABAuthorizationStatusDenied || status == kABAuthorizationStatusRestricted)) {
    NSLog(@"User previously denied permission; show error message that they must go to settings and give this app permission");
    return;
} else if (status == kABAuthorizationStatusNotDetermined) {
    CFErrorRef error;
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
    if (!addressBook) {
        NSLog(@"unable to open address book: %@", CFBridgingRelease(error));
        return;
    }

    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
        if (granted) {
            NSLog(@"OK");
        } else {
            NSLog(@"Not ok");
        }

        CFRelease(addressBook);
    });
}

下面是如何获取联系人ID的解决方案:

- (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.
    ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus();
    if ((status == kABAuthorizationStatusDenied || status == kABAuthorizationStatusRestricted)) {
        NSLog(@"User previously denied permission; show error message that they must go to settings and give this app permission");
        return;
    } else if (status == kABAuthorizationStatusNotDetermined) {
        CFErrorRef error;
        ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
        if (!addressBook) {
            NSLog(@"unable to open address book: %@", CFBridgingRelease(error));
            return;
        }

        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
            if (granted) {
                NSLog(@"OK");
            } else {
                NSLog(@"Not ok");
            }

            CFRelease(addressBook);
        });
    }

    ABPeoplePickerNavigationController* picker = [[ABPeoplePickerNavigationController alloc] init];
    picker.peoplePickerDelegate = self;
    [self presentViewController:picker animated:YES completion:nil];
}

-(void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person
{
    [peoplePicker dismissViewControllerAnimated:YES completion:nil];
    ABRecordID recordID = ABRecordGetRecordID(person);
    NSLog([NSString stringWithFormat:@"%@"], recordID);
}

感谢帮助我的Rob:)

顺便说一句,请注意授权完成块不会在主线程上运行,因此您在该块中执行的任何UI操作都必须发送回主队列。非常感谢。现在它对我有效:)通过我的解决方案和Rob的工作,您可以获得联系人的ID;)这对我也有用。通过上面的更改,ABRecordGetRecordID不再像以前一样返回-1(kABRecordInvalidID)。文档称ABRecordGetRecordID在“记录尚未保存到数据库时”返回kABRecordInvalidID。对此,我当然要补充:“如果应用程序尚未使用ABAddressBookRequestAccessWithCompletion请求访问通讯簿,也会返回kABRecordInvalidID(…).好的,我改了,用正确的答案回答了我的问题;)谢谢你的时间和帮助。:)