Ios 将kCFFTPResourceType与数字进行比较

我正在编写一个FTP下载系统，清单功能：

NSLog(@"%@", listDir.filesInfo);

我在服务器上看到我的文件：

{
    kCFFTPResourceGroup = group;
    kCFFTPResourceLink = "";
    kCFFTPResourceModDate = "2012-11-04 15:49:00 +0000";
    kCFFTPResourceMode = 511;
    kCFFTPResourceName = "eyeview__0000_sport_general.jpg";
    kCFFTPResourceOwner = owner;
    kCFFTPResourceSize = 169790;
    kCFFTPResourceType = 8;
},
    {
    kCFFTPResourceGroup = group;
    kCFFTPResourceLink = "";
    kCFFTPResourceModDate = "2012-11-04 15:49:00 +0000";
    kCFFTPResourceMode = 511;
    kCFFTPResourceName = "eyeview__0001_sport_reading.jpg";
    kCFFTPResourceOwner = owner;
    kCFFTPResourceSize = 224795;
    kCFFTPResourceType = 8;
},

我想做的下一件事是：

for (NSDictionary *file in listDir.filesInfo)
    {
        NSLog(@"%@", [file objectForKey:(id)kCFFTPResourceName]); //Prints the file name

        if ([file objectForKey:(id)kCFFTPResourceType]==8) //*My problem
        {
            [filesList addObject:[file objectForKey:(id)kCFFTPResourceName]]; //Works perfectly in case outside the if function
        }


    }

---

*我的问题是比较错误，如何编写它才能工作？

[file objectForKey:

不会返回

int

。它返回一个

NSNumber

（也称为

CFNumberRef

）

演示：

---

[file objectForKey:

不会返回

int

。它返回一个

NSNumber

（也称为

CFNumberRef

）

演示：

---

当需要kCFFTPResourceType详细信息时，这可能很有用

---

当需要kCFFTPResourceType详细信息时，这可能会很有用

NSNumber * n = [file objectForKey:(id)kCFFTPResourceType];
const int i = n.intValue;
if (8 == i) {
  [filesList addObject:[file objectForKey:(id)kCFFTPResourceName]];
}