如何从iphone/ipad当前日期开始查找第三天的日期

有人能告诉我如何从iphone/ipad的当前日期中找出第三天的日期吗

提前感谢

类似于：

NSDate *today = [NSDate date];
NSTimeInterval threeDays = 86400*3;

NSDate *threeDaysFromToday = [NSDate dateWithTimeInterval:threeDays sinceDate:today];

// get the gregorian calendar ready to go; use the getter for the current system
// calendar if you're happy to deal with other calendars too
NSCalendar *gregorianCalendar = [[NSCalendar alloc]
                                initWithCalendarIdentifier: NSGregorianCalendar];

// get an NSDate object that is three days in the future
NSDate *dateInFuture = [NSDate dateWithTimeIntervalSinceNow:3*24*60*60];

// grab the date components for the bits we want to print in this example
NSDateComponents *componentsOfDateInFuture = 
       [gregorianCalendar
        components:NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit
          fromDate:dateInFuture];

// and print
NSLog(@"in three days it'll be %04d/%02d/%02d", 
           componentsOfDateInFuture.year,
           componentsOfDateInFuture.month, 
           componentsOfDateInFuture.day);

// clean up
[gregorianCalendar release];

编辑：考虑到夏令时的问题，巴勃罗·圣克鲁斯的答案更适合于确保你在未来三天的工作时间。这是您将NSDate分解为日/月/年的方式，目的是获得日期而不是简单的NSDate。

类似于：

// get the gregorian calendar ready to go; use the getter for the current system
// calendar if you're happy to deal with other calendars too
NSCalendar *gregorianCalendar = [[NSCalendar alloc]
                                initWithCalendarIdentifier: NSGregorianCalendar];

// get an NSDate object that is three days in the future
NSDate *dateInFuture = [NSDate dateWithTimeIntervalSinceNow:3*24*60*60];

// grab the date components for the bits we want to print in this example
NSDateComponents *componentsOfDateInFuture = 
       [gregorianCalendar
        components:NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit
          fromDate:dateInFuture];

// and print
NSLog(@"in three days it'll be %04d/%02d/%02d", 
           componentsOfDateInFuture.year,
           componentsOfDateInFuture.month, 
           componentsOfDateInFuture.day);

// clean up
[gregorianCalendar release];

编辑：考虑到夏令时的问题，巴勃罗·圣克鲁斯的答案更适合于确保你在未来三天的工作时间。这是您将NSDate分解为日/月/年的方式，目的是获得日期而不是简单的NSDate。

选择一个：

NSDate *futureDate;
NSDateComponents *components = [[[NSDateComponents alloc] init] autorelease];
[components setDay:3];
futureDate = [[NSCalendar currentCalendar] dateByAddingComponents:components toDate:[NSDate date] options:0];
NSLog(@"%@ - %@", [NSDate date], futureDate);



NSDate *futureDate = [[NSDate date] dateByAddingTimeInterval:3 * (24*60*60)];

选择一个：

NSDate *futureDate;
NSDateComponents *components = [[[NSDateComponents alloc] init] autorelease];
[components setDay:3];
futureDate = [[NSCalendar currentCalendar] dateByAddingComponents:components toDate:[NSDate date] options:0];
NSLog(@"%@ - %@", [NSDate date], futureDate);



NSDate *futureDate = [[NSDate date] dateByAddingTimeInterval:3 * (24*60*60)];

您可以使用以下选项：

NSDate *today = [[NSDate alloc] init];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
[offsetComponents setDay:3];
NSDate *threeDaysFromToday = [gregorian dateByAddingComponents:offsetComponents toDate:today options:0];

从中稍微修改示例。有关更多信息和示例，请查看链接。

您可以使用以下方法：

NSDate *today = [[NSDate alloc] init];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
[offsetComponents setDay:3];
NSDate *threeDaysFromToday = [gregorian dateByAddingComponents:offsetComponents toDate:today options:0];

[NSDate dateWithTimeIntervalSinceNow:86400*3]

从中稍微修改示例。查看链接了解更多信息和示例

[NSDate dateWithTimeIntervalSinceNow:86400*3]

但正如上面提到的，DST可能会使这太不准确。这取决于它的重要性

但正如上面提到的，DST可能会使这太不准确。取决于它的重要性。

以下是示例代码

    NSDate  * currentDate=[NSDate date];
NSTimeInterval interval=[currentDate timeIntervalSince1970];
NSTimeInterval intervalForThirdDate=interval+86400*3;
NSDate *nextDate=[[NSDate alloc]initWithTimeIntervalSince1970:intervalForThirdDate];

下面是示例代码

    NSDate  * currentDate=[NSDate date];
NSTimeInterval interval=[currentDate timeIntervalSince1970];
NSTimeInterval intervalForThirdDate=interval+86400*3;
NSDate *nextDate=[[NSDate alloc]initWithTimeIntervalSince1970:intervalForThirdDate];

---

应该在夏令时小心使用。谢谢Christo，你的答案是静态的，所以我尝试了Louis Gerbarg的帖子中的这个示例-在下面的url=谢谢Christo应该在夏令时小心使用。谢谢Christo，你的答案是静态的，所以我尝试了Louis Gerbarg的帖子中的这个示例-在下面的url=谢谢CristoI我不确定你的意思是将间隔乘以86400；1970年后的约会时间是现在的86400倍。据我所知，他/她没有这样做，是吗？他把86400*3加到间隔上。不过，对于他所采取的方法来说，这个例子似乎有点复杂。我不确定你的意思是将间隔乘以86400；1970年后的约会时间是现在的86400倍。据我所知，他/她没有这样做，是吗？他把86400*3加到间隔上。然而，对于他所采取的方法来说，这个例子似乎有点复杂。