iPhone:SBJSON解析器解析JSON时出错

您好，我正在制作一个iPhone应用程序，在这个应用程序中，我从webservice获得JSON格式的响应。我正在使用SBJSON解析器解析我的数据

我尝试解析数据时出错

我参考了以下链接，但没有一个有帮助：

有什么不对劲吗

感谢您的帮助

代码：

 NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL: [NSURL URLWithString: @"<MyWebserviceURL>"]];

    /* Following function is used to convert and concate json string with url and create query string to exicute to the server.*/
    [request addValue: @"application/json; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [request addValue: @"application/json; charset=utf-8" forHTTPHeaderField:@"Accept"];
    NSString *msgLength = [NSString stringWithFormat:@"%d", [soapMessage length]];
    [request addValue: msgLength forHTTPHeaderField:@"Content-Length"];
    [request setHTTPMethod:@"POST"];
    [request setHTTPBody: [soapMessage dataUsingEncoding:NSUTF8StringEncoding]];

    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse: nil error: nil];

    /* This string will convert all the data format to string format and store it.*/
    NSString *myString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
    NSLog(@"getresponse:%@",myString);
    /* This string will used get json value and split the value starting from "d".*/
    //NSDictionary *d = [[myString JSONValue] objectForKey:@"d"];
    NSLog(@"[myString JSONValue]: %@",[[myString JSONValue] class]);
    NSDictionary *d = [[myString JSONValue]  valueForKey:@"d"];  //  <----- ERROR IS SHOWN HERE

NSMutableURLRequest*request=[[NSMutableURLRequest alloc]initWithURL:[nsurlurlwithstring:@”“]；
/*下面的函数用于转换json字符串并将其与url关联，以及创建查询字符串以退出到服务器*/
[RequestAddValue:@“application/json；charset=utf-8”forHTTPHeaderField:@“Content Type”]；
[request addValue:@“application/json；charset=utf-8”forHTTPHeaderField:@“Accept”]；
NSString*msgLength=[NSString stringWithFormat:@“%d”，[soapMessage length]]；
[请求添加值：msgLength forHTTPHeaderField:@“内容长度”]；
[请求设置HttpMethod:@“POST”]；
[请求setHTTPBody:[soapMessage dataUsingEncoding:NSUTF8StringEncoding]；
NSData*returnData=[NSURLConnection sendSynchronousRequest:request returningResponse:nil错误：nil]；
/*此字符串将所有数据格式转换为字符串格式并存储*/
NSString*myString=[[NSString alloc]initWithData:returnData编码：NSUTF8StringEncoding]；
NSLog（@“getresponse:%@”，myString）；
/*该字符串将用于获取json值，并从“d”开始拆分该值*/
//NSDictionary*d=[[myString JSONValue]objectForKey:@“d”]；
NSLog（@“[myString JSONValue]：%@”，[[myString JSONValue]类]；
NSDictionary*d=[[myString JSONValue]valueForKey:@“d”]；// 您需要使用NSDictionary方法
-objectForKey:
，而不是键值编码方法
-valueForKey:
。这些不（总是）可互换。
如果
SBJSON
坏了怎么办？JSON看起来不错。为什么不使用
NSJSONSerialization
？可能是因为json。在NSLog中获取json并使用以下链接验证它…@Anil Kothari我已经验证了它。问题出现在NSDictionary*d=[[myString JSONValue]valueForKey:@“d”]；
    getresponse:{"d":{"__type":"<CompanyName>.<AppName>.BusinessLogic.RegisterWebservice","ErrorObject":{"__type":"<CompanyName>.<AppName>.BusinessLogic.Error","ErrorMessage":"","ErrorCode":0},"AttendeeCredentials":{"__type":"<CompanyName>.<AppName>.BusinessLogic.AttendeeCredential","UserID":"abcd","Password":"abcd"},"ServerDeviceSN":"PKKPAPPKAPPKAPK090"}}
    [myString JSONValue]: __NSCFString

    *** Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[<__NSCFString 0xc384f30> valueForUndefinedKey:]: this class is not key value coding-compliant for the key d.'
*** First throw call stack:
(0x2eaa012 0x2b1ae7e 0x2f32fb1 0x13aa5ed 0x13168db 0x131688d 0xf6aef 0xf64b9 0xfecef 0xfe834 0x13490d5 0x1349034 0x950d8ed9 0x950dc6de)
libc++abi.dylib: terminate called throwing an exception