Iphone 如何在数组中查找重复值?
我正在处理SQLite,我编写了一个查询,返回两个数组ItemsArray和CustomerSiArray,如下所示:Iphone 如何在数组中查找重复值?,iphone,ios,xcode4.2,ios-simulator,Iphone,Ios,Xcode4.2,Ios Simulator,我正在处理SQLite,我编写了一个查询,返回两个数组ItemsArray和CustomerSiArray,如下所示: ItemsArray Element at Index 0 = Off White, Element at Index 1 = Fan, Element at Index 2 = Off White, Element at Index 3 = Delux, Element at Index 4 = Fan CustomerIDArray Element at Index 0
ItemsArray
Element at Index 0 = Off White,
Element at Index 1 = Fan,
Element at Index 2 = Off White,
Element at Index 3 = Delux,
Element at Index 4 = Fan
CustomerIDArray
Element at Index 0 = 1,
Element at Index 1 = 2,
Element at Index 2 = 2,
Element at Index 3 = 3,
Element at Index 4 = 4
我想要这样的结果:灰白色=2(计数),扇形=2(计数)和消光=1;
以及生成的数组
Result Array
Element at Index 0 = Off White,
Element at Index 1 = Fan,
Element at Index 2 = Delux
实际上,我想要第一个数组中的重复计数,但CustomerArray的值不能相同。
请通过逻辑或代码帮助我。尝试以下操作:
NSArray *copy = [ItemsArray copy];
NSInteger index = [copy count] - 1;
for (id object in [copy reverseObjectEnumerator]) {
if ([ItemsArray indexOfObject:object inRange:NSMakeRange(0, index)] != NSNotFound) {
[ItemsArray removeObjectAtIndex:index];
}
index--;
}
使用
NSCountedSet
如下所示
NSMutableArray *ary_res = [[NSMutableArray alloc] init];
NSMutableArray *array = [[NSMutableArray alloc] initWithObjects:@"11",@"13",@"34",@"9",@"13",@"34",@"9",@"2",nil];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:array];
for(id name in set)
{
if([set countForObject:name]==2)
[ary_res addObject:name];
}
//
NSLog(@"%@",ary_res);
-(NSMutableArray*)getCountAndRemoveMultiples:(NSMutableArray*)数组{
NSMutableArray*newArray=[[NSMutableArray alloc]initWithArray:(NSArray*)数组];
NSMUTABLEARRY*countArray=[NSMUTABLEARRY new];
int countInt=1;
对于(int i=0;i
我刚刚设置了-getArrayInfo来测试它。很好。如您所见,要显示的数组将位于索引0处,而countArray位于索引1处。请尝试此问题提供的解决方案:()@INoob亲爱的,我不知道如何使用NSCountedSet。。您能告诉我吗?在这里尝试一下答案:@iNoob如何计算重复元素计数:(@AmirIphone查看我的答案我更改了它,它对我有效。它的更新项目数组。但我还需要重复项目的计数。我建议不要使用名称副本到数组中,因为人们可能会与您在中使用的消息副本混淆:NSArray*copy=[ItemsArray copy];我需要在数组中生成结果,如果两次,则再次保存2项,如果三次,则保存3项,如果一次,则保存1项。是的……但我还想知道它在数组中出现了多少次这真是太好了,我根据自己提交了一些更改……竖起大拇指:)我还有一个问题,你能帮我吗?当然可以--发布一个问题,并在这里留下一个链接作为评论。上面的回答在逻辑上是不正确的。请使用此输入尝试NSMutableArray*myArray=[[NSMutableArray alloc]initWithObjects:@“Off White”、@“Fan”、@“Off White”、@“Deluxe”、@“Fan”、@“Fan”、@“Fan”、nil];。您可以看到“Fan”的计数是3,但实际上是4。若要更正此问题,您需要在从数组中删除元素后减小j(否则数组中的下一个字符串将不计算)。编辑了答案
-(NSMutableArray *)getCountAndRemoveMultiples:(NSMutableArray *)array{
NSMutableArray *newArray = [[NSMutableArray alloc]initWithArray:(NSArray *)array];
NSMutableArray *countArray = [NSMutableArray new];
int countInt = 1;
for (int i = 0; i < newArray.count; ++i) {
NSString *string = [newArray objectAtIndex:i];
for (int j = i+1; j < newArray.count; ++j) {
if ([string isEqualToString:[newArray objectAtIndex:j]]) {
[newArray removeObjectAtIndex:j];
countInt++;
}
}
[countArray addObject:[NSNumber numberWithInt:countInt]];
countInt = 1;
}
NSMutableArray *finalArray = [[NSMutableArray alloc] initWithObjects:newArray, countArray, nil];
NSLog(@"%@", finalArray);
return finalArray;
}
- (IBAction)getArrayInfo:(id)sender {
NSMutableArray *myArray = [[NSMutableArray alloc] initWithObjects:@"Off White", @"Fan", @"Off White", @"Deluxe", @"Fan", nil];
NSMutableArray *godArray = [self getCountAndRemoveMultiples:myArray];
NSLog(@"Array from this end = %@", godArray);
}