Java JAXB封送XmlAdapter创建的ArrayList
我想使用Java JAXB封送XmlAdapter创建的ArrayList,java,arraylist,jaxb,marshalling,xmladapter,Java,Arraylist,Jaxb,Marshalling,Xmladapter,我想使用XmlAdapter调整HashMap字段的XML表示。我使用ArrayList来实现这一点。但是,在编组时,根本不会编组ArrayList。为什么呢 代码 @XmlRootElement public class Foo { private HashMap<String, String> hashMap; public Foo() { this.hashMap = new HashMap<String, String>();
XmlAdapter
调整HashMap
字段的XML表示。我使用ArrayList
来实现这一点。但是,在编组时,根本不会编组ArrayList
。为什么呢
代码
@XmlRootElement
public class Foo {
private HashMap<String, String> hashMap;
public Foo() {
this.hashMap = new HashMap<String, String>();
}
@XmlJavaTypeAdapter(HashMapAdapter.class)
public HashMap<String, String> getHashmap() {
return hashMap;
}
public void setHashmap(HashMap<String, String> hashMap) {
this.hashMap = hashMap;
}
}
结果
在
XmlAdapter
中,您需要将HashMap
转换为具有List
属性的对象实例,而不是直接转换为ArrayList
HashMapAdapter
package forum13163430;
import java.util.*;
import java.util.Map.Entry;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlAdapter;
public final class HashMapAdapter extends XmlAdapter<HashMapAdapter.AdaptedHashMap, HashMap<String, String>> {
@Override
public AdaptedHashMap marshal(HashMap<String, String> hashMap) throws Exception {
AdaptedHashMap adaptedHashMap = new AdaptedHashMap();
for(Entry<String, String> entry : hashMap.entrySet()) {
adaptedHashMap.item.add(new HashMapEntry(entry.getKey(), entry.getValue()));
}
return adaptedHashMap;
}
@Override
public HashMap<String, String> unmarshal(AdaptedHashMap adaptedHashMap) throws Exception {
HashMap<String, String> result = new HashMap<String, String>();
for(HashMapEntry entry : adaptedHashMap.item)
result.put(entry.key, entry.value);
return result;
}
public static class AdaptedHashMap {
public List<HashMapEntry> item = new ArrayList<HashMapEntry>();
}
public static class HashMapEntry {
@XmlAttribute
public String key;
@XmlValue
public String value;
public HashMapEntry() {
}
public HashMapEntry(String key, String value) {
this.key = key;
this.value = value;
}
}
}
jaxb.properties
要将MOXy指定为JAXB提供程序,您需要在与域模型相同的包中包含一个名为JAXB.properties
的文件,其中包含以下条目(请参阅:)
演示
由于MOXy是JAXB(JSR-222)兼容的实现,因此可以使用标准api将对象从XML转换为XML
package forum13163430;
import java.io.File;
import javax.xml.bind.*;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Foo.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
File xml = new File("src/forum13163430/input.xml");
Foo foo = (Foo) unmarshaller.unmarshal(xml);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(foo, System.out);
}
}
input.xml/Output
下面是运行演示代码的输入和输出
B
C
A.
了解更多信息
@XmlPath
扩展来实现这一点。我是莫西领队。
javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory
package forum13163430;
import java.io.File;
import javax.xml.bind.*;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Foo.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
File xml = new File("src/forum13163430/input.xml");
Foo foo = (Foo) unmarshaller.unmarshal(xml);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(foo, System.out);
}
}