Java HashMap映射的值稍微关闭
阵列主义者Java HashMap映射的值稍微关闭,java,arrays,hashmap,Java,Arrays,Hashmap,阵列主义者 This is jumblesOrdered: [act, aprt, art, dgo, fgor, opst] This is jumbles: [arpt, atc, atr, gdo, grof, otsp] 输出: This is jumbleWordHM: {opst=otsp, art=atr, fgor=grof, dgo=gdo, aprt=atc, act=arpt} HashMap的代码: for (int i = 0; i < ju
This is jumblesOrdered: [act, aprt, art, dgo, fgor, opst]
This is jumbles: [arpt, atc, atr, gdo, grof, otsp]
输出:
This is jumbleWordHM: {opst=otsp, art=atr, fgor=grof, dgo=gdo, aprt=atc, act=arpt}
HashMap的代码:
for (int i = 0; i < jumblesOrdered.size(); i++) {
String word = jumbles.get(i);
String sortedWord = jumblesOrdered.get(i);
if (jumbleWordHM.get(sortedWord) == null) {
jumbleWordHM.put(sortedWord, word);
} else {
jumbleWordHM.put(sortedWord, jumbleWordHM.get(sortedWord) + " "
+ word);
}
}
**表示需要切换的内容 您的第一个ArrayList以以下内容开头:
- [act,aprt,…]
- [arpt,atc
如果不能保证顺序,则需要添加代码以查找包含相同字母的字符串。为什么要将
act
放在混乱中的第一位和arpt
放在混乱中的第一位?混乱顺序是每个字符串中每个字母的字母顺序act
不是按字母顺序排列的arpt
秩序。
This is jumbleWordHM: {opst=otsp, art=atr, fgor=grof, dgo=gdo, ****aprt=arpt, ****act=atc}