Java 不允许对ResultSet.type\u FORWARD\u类型的结果集执行操作

我有以下代码：

    public static ArrayList<TicketData> readDB(Connection pConnection) 
{
    TicketData lSingleTicketData;
    ArrayList<TicketData> lTicketData = new ArrayList<TicketData>();
    Statement lStatement;
    ResultSet lResultSet;

    try 
    {
        lStatement = pConnection.createStatement();
        lResultSet = lStatement.executeQuery("SELECT * FROM test.ticket");
        lResultSet.first();

        while(!lResultSet.isAfterLast())
        {
            lSingleTicketData = new TicketData(lResultSet.getString(1) ,lResultSet.getDate(2).toLocalDate(),lResultSet.getInt(3));
            lTicketData.add(lSingleTicketData);
            lResultSet.next();
        }
     } 
    catch (Exception ex)
    {
        System.out.println("Error at the execution + " + ex.getMessage());
    } 
  return lTicketData; 
}

---

这是什么原因造成的？我如何修复它？提前感谢。

请阅读Javadoc中的

ResultSet.first（）

：

迭代结果集的常用方法是：

while (rs.next()) {
...
}

---

您使问题变得比您需要的复杂得多。

请编辑您的问题并添加异常的完整堆栈跟踪。

    /**
     * Moves the cursor to the first row in
     * this <code>ResultSet</code> object.
     *
     * @return <code>true</code> if the cursor is on a valid row;
     * <code>false</code> if there are no rows in the result set
     * @exception SQLException if a database access error
     * occurs; this method is called on a closed result set
     * or the result set type is <code>TYPE_FORWARD_ONLY</code>
     * @exception SQLFeatureNotSupportedException if the JDBC driver does not support
     * this method
     * @since 1.2
     */
    boolean first() throws SQLException;

while (rs.next()) {
...
}