Java 如何解析一个字符串并获取每一个子字符串一次?
我想制作一个程序,让它按照顺序返回一个ArrayList和一个字符串中的每个子字符串Java 如何解析一个字符串并获取每一个子字符串一次?,java,string,substring,Java,String,Substring,我想制作一个程序,让它按照顺序返回一个ArrayList和一个字符串中的每个子字符串 static boolean tropChangements(String branche, int ocurrTaches) { ArrayList dispositif = new ArrayList(); String pub = "[public]"; String priv = "[private]"; String branc
static boolean tropChangements(String branche, int ocurrTaches) {
ArrayList dispositif = new ArrayList();
String pub = "[public]";
String priv = "[private]";
String brancheDecoup;
int ptVirg = branche.indexOf(" ; ");
for(int i = 0; i<ocurrTaches; i++) {
brancheDecoup = [...] //use ptVirg
if (brancheDecoup.contains(pub)) {
dispositif.add("public");
} else if (branche.contains(priv)) {
dispositif.add("private");
}
}
//[...] It's OK here
}
所以,我想在BrancheDecoup中只显示我的子字符串的第一次出现,以及下一个、下一个等。字符串的结尾是一个
我的字符串,例如:
EcrireNomEtudiant[公共];EnterMDP[私人];AvecQui[私人];唱诗班;VerifDisponibilite[系统];宣誓就职[私人];特使拉德曼德[系统]
我希望这个结果->
在ArrayList中:public、private、private、perso、private
事先非常感谢
致以最良好的祝愿,
Vincent。您可以先拆分字符串,然后使用正则表达式匹配模式
Pattern p = Pattern.compile("\\[(.*?)]");
String str = "EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system]";
Function<String, String> finder = s -> {
Matcher m = p.matcher(s);
return m.find() ? m.group(1) : null;
};
List<String> list = Arrays.stream(str.split(";"))
.map(finder)
.collect(Collectors.toList());
System.out.println(list);
您可以先拆分字符串,然后使用正则表达式匹配模式
Pattern p = Pattern.compile("\\[(.*?)]");
String str = "EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system]";
Function<String, String> finder = s -> {
Matcher m = p.matcher(s);
return m.find() ? m.group(1) : null;
};
List<String> list = Arrays.stream(str.split(";"))
.map(finder)
.collect(Collectors.toList());
System.out.println(list);
试试这个:
import java.util.HashSet;
import java.util.Set;
public class Main {
public static void main(String[] args) {
String sample = "EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system].";
tropChangements(sample);
}
static void tropChangements(String branche) {
Set<String> dispositif = new HashSet<String>(); // use Set so that there will be no duplicates
String[] branches = branche.split(";"); // use split method to split string by ";"
for (String s : branches) { // iterate string
int indexOfOpen = s.indexOf("["); // get the index of "["
int indexOfClose = s.lastIndexOf("]"); // get the index of "]"
if (indexOfOpen > 0 && indexOfClose > 0) { // check if both "[" and "]" is found
String tmp = s.substring(indexOfOpen + 1, indexOfClose); // get the needed string
dispositif.add(tmp); //add it to the set
}
}
System.out.println(dispositif); // print the set
}
}
结果:[个人、私人、系统、公共]尝试以下操作:
import java.util.HashSet;
import java.util.Set;
public class Main {
public static void main(String[] args) {
String sample = "EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system].";
tropChangements(sample);
}
static void tropChangements(String branche) {
Set<String> dispositif = new HashSet<String>(); // use Set so that there will be no duplicates
String[] branches = branche.split(";"); // use split method to split string by ";"
for (String s : branches) { // iterate string
int indexOfOpen = s.indexOf("["); // get the index of "["
int indexOfClose = s.lastIndexOf("]"); // get the index of "]"
if (indexOfOpen > 0 && indexOfClose > 0) { // check if both "[" and "]" is found
String tmp = s.substring(indexOfOpen + 1, indexOfClose); // get the needed string
dispositif.add(tmp); //add it to the set
}
}
System.out.println(dispositif); // print the set
}
}
结果:[个人、私人、系统、公共]我不确定我是否完全理解您试图做的事情,但这将为您提供您期望的输出:
List<String> dispositif = new ArrayList<>();
Pattern re = Pattern.compile("\\[(public|private|perso)\\]");
Matcher matcher = re.matcher(branche);
while (matcher.find()) {
dispositif.add(matcher.group(1));
}
我不确定我是否完全理解您试图做的事情,但这将为您提供您期望的输出:
List<String> dispositif = new ArrayList<>();
Pattern re = Pattern.compile("\\[(public|private|perso)\\]");
Matcher matcher = re.matcher(branche);
while (matcher.find()) {
dispositif.add(matcher.group(1));
}
考虑lib的使用,这使得上面的@sidgate代码更加清晰
因此,完整的列表将是:
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
import org.apache.commons.lang.StringUtils;
public class Example {
static String sample =
"EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system]";
public static void main(String[] args) {
tropChangements(sample);
}
static void tropChangements(String branche) {
List<String> list = Arrays
.stream(branche.split(";"))
.map(String::trim)
.map(s -> StringUtils.substringBetween(s, "[", "]"))
.collect(Collectors.toList());
System.out.println(list);
}
}
考虑lib的使用,这使得上面的@sidgate代码更加清晰
因此,完整的列表将是:
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
import org.apache.commons.lang.StringUtils;
public class Example {
static String sample =
"EcrireNomEtudiant[public] ; EntrerMDP[private] ; AvecQui[private] ; ChoisirJour[perso] ; VerifDisponibilites[system] ; AfficherRecupilatif[private] ; EnvoyerLaDemande[system]";
public static void main(String[] args) {
tropChangements(sample);
}
static void tropChangements(String branche) {
List<String> list = Arrays
.stream(branche.split(";"))
.map(String::trim)
.map(s -> StringUtils.substringBetween(s, "[", "]"))
.collect(Collectors.toList());
System.out.println(list);
}
}
你知道Stringsplit函数吗?如果是,那就试试看。您的代码将变得更容易您知道Stringsplit函数吗?如果是,那就试试看。您的代码将变得更加简单