Java Hibernate 4 EntityManager CriteriaBuilder sortby嵌套属性_Java_Spring_Hibernate_Jpa_Hibernate Entitymanager

Java Hibernate 4 EntityManager CriteriaBuilder sortby嵌套属性

java spring hibernate jpa

Java Hibernate 4 EntityManager CriteriaBuilder sortby嵌套属性,java,spring,hibernate,jpa,hibernate-entitymanager,Java,Spring,Hibernate,Jpa,Hibernate Entitymanager,我的模型： public class Nested { private Integer id; private String sortBy; [...] } public class ObjectToQuery { private Integer id; private Nested nested; private OtherProperty otherProperty; [...] } 我的元模型： @StaticMetamodel(

我的模型：

public class Nested {
    private Integer id;
    private String sortBy;
    [...]
}

public class ObjectToQuery {
    private Integer id;
    private Nested nested;
    private OtherProperty otherProperty;
    [...]
}

我的元模型：

@StaticMetamodel(Nested.class)
public class Nested_ {
    public static volatile SingularAttribute<Nested, Integer> id;
    public static volatile SingularAttribute<Nested, String> sortBy;
[...]
}
@StaticMetamodel(ObjectToQuery.class)
public class ObjectToQuery_ {
    public static volatile SingularAttribute<ObjectToQuery, Integer> id;
    public static volatile SingularAttribute<ObjectToQuery, Nested> nested;
    public static volatile SingularAttribute<ObjectToQuery, OtherProperty> otherProperty;
    [...]
}

（按嵌套的.id进行排序）

但我想按

ObjectToQuery.Nested.sortBy

我使用Hibernate 4.2.6.FINAL作为我的JPA实现

我自己找到了答案：

Join<ObjectToQuery, Nested> join = rootObjectToQuery
    .join(ObjectToQuery_.nested);
criteriaQuery.orderBy(criteriaBuilder.asc(join
    .get(Nested_.sortBy)));

Join-Join=rootObjectToQuery
.join（ObjectToQuery\uu.nested）；
criteriaQuery.orderBy（criteriaBuilder.asc（join
.get（Nested_u.sortBy））；

我希望这对某人有帮助

ObjectToQuery.Nested.sortBy

Join<ObjectToQuery, Nested> join = rootObjectToQuery
    .join(ObjectToQuery_.nested);
criteriaQuery.orderBy(criteriaBuilder.asc(join
    .get(Nested_.sortBy)));