Java 如何加载驻留在S3 bucket中的zip文件？

我有一种情况，需要打开驻留在S3 bucket中的zip文件。 到目前为止，我的代码如下所示：

public ZipFile readZipFile(String name) throws Exception {
    GetObjectRequest req = new GetObjectRequest(settings.getAwsS3BatchRecogInBucketName(), name);
    S3Object obj = s3Client.getObject(req);
    S3ObjectInputStream is = obj.getObjectContent();

    /******************************
     * HOW TO DO
     ******************************/
    return null;
}

public ZipFile readZipFile(String name) throws Exception {
    GetObjectRequest req = new GetObjectRequest(settings.getAwsS3BatchRecogInBucketName(), name);
    S3Object obj = s3Client.getObject(req);
    S3ObjectInputStream is = obj.getObjectContent();

    File temp = File.createTempFile(name, "");
    temp.setWritable(true);
    FileOutputStream fos = new FileOutputStream(temp);
    fos.write(IOUtils.toByteArray(is));
    fos.flush();
    return new ZipFile(temp);
}

以前我确实尝试过创建一个临时文件对象，并使用file.createTempFile函数，但我总是在没有创建文件对象的地方遇到麻烦。我之前的尝试如下所示：

public ZipFile readZipFile(String name) throws Exception {
    GetObjectRequest req = new GetObjectRequest(settings.getAwsS3BatchRecogInBucketName(), name);
    S3Object obj = s3Client.getObject(req);
    S3ObjectInputStream is = obj.getObjectContent();

    /******************************
     * HOW TO DO
     ******************************/
    return null;
}

public ZipFile readZipFile(String name) throws Exception {
    GetObjectRequest req = new GetObjectRequest(settings.getAwsS3BatchRecogInBucketName(), name);
    S3Object obj = s3Client.getObject(req);
    S3ObjectInputStream is = obj.getObjectContent();

    File temp = File.createTempFile(name, "");
    temp.setWritable(true);
    FileOutputStream fos = new FileOutputStream(temp);
    fos.write(IOUtils.toByteArray(is));
    fos.flush();
    return new ZipFile(temp);
}

---

有人遇到过这种情况吗？请告诉我谢谢：）

如果您想立即使用zip文件而不首先将其保存到临时文件，您可以使用

java.util.zip.ZipInputStream

：

import java.util.zip.ZipInputStream;

S3ObjectInputStream is = obj.getObjectContent();
ZipInputStream zis = new ZipInputStream(is);

从这里开始，您可以通读zip文件的条目，忽略不需要的条目，并使用需要的条目：

ZipEntry entry;
while ((entry = zis.getNextEntry()) != null) {
    String name = entry.getName();
    if (iWantToProcessThisEntry(name)) {
        processFile(name, zis);
    }
    zis.closeEntry();
}

public void processFile(String name, InputStream in) throws IOException { /* ... */ }

您不必担心以这种方式存储临时文件