Java 检查字符串中数值的外观（并从中提取）

我正在尝试使用Eclipse中的Selenium通过提交按钮自动化工作流

我正在使用一个自定义函数waitForVisible来检查id为“naviInfo”的WebElement是否显示，以及它是否包含一条消息，该消息包含“未找到任何行”或“已找到{number}行”消息

问题是我无法对文本的数字部分进行排序和检查。下面给出了示例代码

String message = waitForVisible(By.id("naviInfo")).getText();

if ("No rows were found".equals(message)) {
      log.info("No rows were found after submit");
}
else if ("**1804** rows were found".equals(message)) {
      log.info("**1804** rows found after submit");
}
else {
      (other error checks)
}

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如何检查在公共文本“rows was found”之前是否找到了一个数值？另外，还可以将此数字保存到变量中？

如果我没有弄错，您只需要询问如何验证消息是否与预期模式匹配，以及如何从字符串中提取数字？在这种情况下，这与硒无关，而是一个简单的正则表达式问题

Pattern p = Pattern.compile("^\\*{2}(\\d+)\\*{2} rows were found$"); //pattern that says: start of string, followed by two *s, then some digits, then two *s again, then the string " rows were found", and finally the end of string, capturing the digits only
Matcher m = p.matcher("**1804** rows were found");    
boolean found = m.find(); //find and capture the pattern of interest
if (found)
   int count = Integer.parseInt(m.group(1)); //get the first (and only) captured group, and parse the integer from it

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请阅读Java正则表达式。

这就是我如何使我的条件起作用的

if (" no rows were found".equals(waitForVisible(By.id("naviInfo")).getText()))
     waitForVisible(By.xpath("//td[contains(text(),'Nothing found to display.')]"));
else if (Pattern.matches("^ \\d+ rows were found$", waitForVisible(By.id("naviInfo")).getText()))
     waitForVisible(By.xpath("//tbody//tr//td/a"));
else
     other error checks

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谢谢卡卡。你的评论真的帮我弄明白了我需要什么。