Java 在不下载WSDL的情况下实例化JAX-WS服务?
我有一个web服务,我有JAX-WS生成的客户端绑定,如下所示:Java 在不下载WSDL的情况下实例化JAX-WS服务?,java,web-services,wsdl,jax-ws,Java,Web Services,Wsdl,Jax Ws,我有一个web服务,我有JAX-WS生成的客户端绑定,如下所示: // web service client generated by JAX-WS @WebServiceClient( ... ) public class WebService_Service extends Service { public WebService_Service(URL wsdlLocation, QName serviceName) { super(wsdlLocation, se
// web service client generated by JAX-WS
@WebServiceClient( ... )
public class WebService_Service extends Service {
public WebService_Service(URL wsdlLocation, QName serviceName) {
super(wsdlLocation, serviceName);
}
WebService getWebServiceSOAP() {
// ...
}
}
我希望能够创建一个指向远程服务的实例,如:
WebService_Service svc = new WebService_Service(
new URL("http://www.example.com/ws?wsdl"),
new QName("http://www.example.com/ws", "WebService"));
但是它从http://www.example.com/ws?wsdl
这是我不想做的
有没有办法停止下载该WSDL,但仍然指向同一个端点?我也遇到了同样的问题,我解决了这个问题,但我无法在您的示例中显示它,因为它取决于WSDL 这是我的代码,跟踪解决方案:
//This is the input object for the webservice
GetDocumentInfoInput input = new GetDocumentInfoInput();
input.setBarcode(barcode);
//I instantiate the WS
MAKSpcIntSpcWFSpcScannerInfo_Service service = new MAKSpcIntSpcWFSpcScannerInfo_Service();
//I get the WS port
MAKSpcIntSpcWFSpcScannerInfo port = service.getMAKSpcIntSpcWFSpcScannerInfo();
WSBindingProvider provider = (WSBindingProvider)port;
//This is the row what set the URL for the WS
provider.getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, url);
//This is the WS calling
GetDocumentInfoOutput output = port.getDocumentInfo(input);
我通过在客户端中为WSDL URL指定null以及显式指定端点地址来解决此问题:
WebService_Service svc = new WebService_Service(
null,
new QName("http://www.example.com/ws", "WebService"));
WebService port = svc.getPort(WebService.class);
BindingProvider bindingProvider = (BindingProvider) port;
bindingProvider.getRequestContext()
.put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
"http://www.example.com/real_endpoint_url_goes_here");
见:
WSDL文件可能包含生成的存根不包含的配置选项,因此在运行时需要这些选项。您可以在类路径中本地提供它们 将我正在使用的服务的WSDL文件放入我的
${basedir}\src\main\resources\META-INF\WSDL
文件夹后,以下maven pom.xml为我工作:
<plugin>
<groupId>org.jvnet.jax-ws-commons</groupId>
<artifactId>jaxws-maven-plugin</artifactId>
<version>2.3</version>
<executions>
<execution>
<id>MyService</id>
<goals>
<goal>wsimport</goal>
</goals>
<configuration>
<!-- this resolves naming conflicts within the wsdl - there are several copies of fault report objects which clash otherwise. -->
<args>
<arg>-B-XautoNameResolution</arg>
</args>
<packageName>de.xyz</packageName>
<wsdlDirectory>${basedir}\src\main\resources\META-INF\wsdl</wsdlDirectory>
<wsdlFiles>
<wsdlFile>MyService.wsdl</wsdlFile>
</wsdlFiles>
<wsdlLocation>META-INF/wsdl/MyService.wsdl</wsdlLocation>
</configuration>
</execution>
[...]
org.jvnet.jax-ws-commons
jaxws-maven插件
2.3
我的服务
wsimport
-B-XautoNameResolution
德克斯
${basedir}\src\main\resources\META-INF\wsdl
MyService.wsdl
META-INF/wsdl/MyService.wsdl
[...]
在运行时,wsdl文件将从类路径加载。我已经看到这也适用于服务的无参数构造函数-在您的例子中是WebService\u service()。我不知道什么是更好的实践,像你一样使用无参数构造函数或(null,QName)构造函数。
@WebServiceClient
注释有一个wsdlLocation
属性,该属性包含指向WSDL的绝对路径。手动删除此项时(您确实不想这样做),我遇到了以下异常:com.sun.xml.ws.streaming.XMLStreamReaderException:xml读取器错误:com.ctc.wstx.exc.WstxUnexpectedCharException:prolog中意外的字符“a”(代码97);顺便说一下,我的平台是WebLogic 12c。另外,你答案中的链接已经失效。谢谢@Dormouse。。。我会更新链接。我的域名必须更改:(我的解决方案类似,使用没有地址的虚拟wsdl,并在运行时设置有效地址: