Java SimpleXML从特定元素获取内部XML

我在从一个字段提取值时遇到问题。示例

XML

如下：

<Rule id="xccdf_org.cisecurity.benchmarks_rule_4.1.2_Ensure_that_the_kubelet_service_file_ownership_is_set_to_rootroot" selected="false" weight="1.000000" role="full">
    <title
        xmlns:xhtml="http://www.w3.org/1999/xhtml" xml:lang="en">Ensure that the kubelet service file ownership is set to root:root
    </title>
    <description
        xmlns:xhtml="http://www.w3.org/1999/xhtml" xml:lang="en">
        <xhtml:p>Ensure that the 
            <xhtml:span class="inline_block">kubelet</xhtml:span> service file ownership is set to 
            <xhtml:span class="inline_block">root:root</xhtml:span>.
        </xhtml:p>
    </description>
</Rule>

课程及类别：

@Root(strict = false, name = "Rule")
public class Rule {
    @Element
    String title;
    @Element(required = false,type = RuleDescription.class)
    RuleDescription description;

    public String getTitle() {
        return title;
    }

    public void setTitle(String title) {
        this.title = title;
    }
}
@Root(strict = false, name = "description")
public class RuleDescription {
    @Element(name = "p", required = false)
    String description;
}

输出为：

-----------------------------------------------
Title: Ensure that the kubelet service file ownership is set to root:root, Desc: Ensure that the 
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这意味着

SimpleXML

只需读取值，并在其路径上出现的第一个标记之前断开。我想得到描述的全部值，即：

确保kubelet服务文件所有权设置为root:root。

或者更好，如果没有像

这样的标记，请确保kubelet服务文件所有权设置为root:root

，但我只需删除标记即可

---

有人能给我一个提示吗？

尝试使用Simple Framework的Convert类。您可能需要编写自己的转换器类来解析上述XML

-----------------------------------------------
Title: Ensure that the kubelet service file ownership is set to root:root, Desc: Ensure that the 
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