Java 如何编写多对多关联表的查询
我有两个实体,它们之间有多对多关系。我想在关联表上写一个查询Java 如何编写多对多关联表的查询,java,sql,hibernate,spring-boot,jpa,Java,Sql,Hibernate,Spring Boot,Jpa,我有两个实体,它们之间有多对多关系。我想在关联表上写一个查询 Here are the two entities. Craftsmen and Skill. I want to write a query which selects all Craftsmen with a given skill. @Entity @Table(name = "craftsman") public class Craftsman { @Id @Gen
Here are the two entities. Craftsmen and Skill.
I want to write a query which selects all Craftsmen with a given skill.
@Entity
@Table(name = "craftsman")
public class Craftsman {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToMany
@JoinTable(name = "craftman_skill", joinColumns = @JoinColumn(name = "craftman_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "skill_id", referencedColumnName = "id"))
private List<Skill> skillList;
}
@Entity
@Table(name = "skill")
public class Skill {
@ManyToMany(mappedBy = "skillList")
@JsonBackReference
private List<Craftsman> craftmanList;
}
以下是我得到的错误:
Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: skill_id of: com.craftsmen.crafts.persistence.Skill [SELECT c FROM com.craftsmen.crafts.persistence.Craftsman c JOIN c.skillList sl WHERE c.skillList.skill_id = :skillId ]
Caused by: org.hibernate.QueryException: could not resolve property: skill_id of: com.craftsmen.crafts.persistence.Skill [SELECT c FROM com.craftsmen.crafts.persistence.Craftsman c JOIN c.skillList sl WHERE c.skillList.skill_id = :skillId ]
我想问题是,您的
技能
实体确实没有技能id,或者更好,没有id
您是否尝试为您的技能
实体提供id
@Entity
@Table(name = "skill")
public class Skill {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToMany(mappedBy = "skillList")
@JsonBackReference
private List<Craftsman> craftmanList;
}
然后将查询
更改为
SELECT c FROM Craftsman c JOIN c.skillList sl WHERE sl.id = :skillId
这是应该的。 也可以考虑使用jpRePi蓄选项:
public interface CraftsmanRepository extends JpaRepository<Craftsman, String> {
public List<Craftsman> getBySkillListIn(@NotEmpty List<Skill> skillList);
c.skillList.skill\u id
试图做什么?你已经加入了!为什么不直接做s1.id
?!!这是JPQL,不是SQL,alsoSkill有一个id,我只是没有发布是偶然的。
@Entity
@Table(name = "craftsman")
public class Craftsman {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToMany
@JoinTable(name = "craftman_skill", joinColumns = @JoinColumn(name = "craftman_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "skill_id", referencedColumnName = "id"))
private List<Skill> skillList;
}
SELECT c FROM Craftsman c JOIN c.skillList sl WHERE sl.id = :skillId
public interface CraftsmanRepository extends JpaRepository<Craftsman, String> {
public List<Craftsman> getBySkillListIn(@NotEmpty List<Skill> skillList);
where <condition> And <>condition And <condition> And...