如何使用JSONObject在Java中创建正确的JSONArray

如何使用JSONObject在Java中创建如下JSON对象

{
    "employees": [
        {"firstName": "John", "lastName": "Doe"}, 
        {"firstName": "Anna", "lastName": "Smith"}, 
        {"firstName": "Peter", "lastName": "Jones"}
    ],
    "manager": [
        {"firstName": "John", "lastName": "Doe"}, 
        {"firstName": "Anna", "lastName": "Smith"}, 
        {"firstName": "Peter", "lastName": "Jones"}
    ]
}

---

我已经找到了很多示例，但并不完全是我的JSONArray字符串。

以下是一些使用java 6的代码：

JSONObject jo = new JSONObject();
jo.put("firstName", "John");
jo.put("lastName", "Doe");

JSONArray ja = new JSONArray();
ja.put(jo);

JSONObject mainObj = new JSONObject();
mainObj.put("employees", ja);

编辑：由于对

put

vs

add

存在很多混淆，我将尝试在这里解释这一区别。java 6中包含

put

方法，java 7中包含

add

方法

在java 7中使用builder模式的示例如下所示：

JsonObject jo = Json.createObjectBuilder()
  .add("employees", Json.createArrayBuilder()
    .add(Json.createObjectBuilder()
      .add("firstName", "John")
      .add("lastName", "Doe")))
  .build();

---

我假设您从服务器或文件获取此JSON，并希望从中创建JSONArray对象

String strJSON = ""; // your string goes here
JSONArray jArray = (JSONArray) new JSONTokener(strJSON).nextValue();
// once you get the array, you may check items like
JSONOBject jObject = jArray.getJSONObject(0);

---

希望这有帮助：）

可以编写可重用的方法来创建person json对象，以避免重复代码

JSONObject  getPerson(String firstName, String lastName){
   JSONObject person = new JSONObject();
   person .put("firstName", firstName);
   person .put("lastName", lastName);
   return person ;
} 

public JSONObject getJsonResponse(){

    JSONArray employees = new JSONArray();
    employees.put(getPerson("John","Doe"));
    employees.put(getPerson("Anna","Smith"));
    employees.put(getPerson("Peter","Jones"));

    JSONArray managers = new JSONArray();
    managers.put(getPerson("John","Doe"));
    managers.put(getPerson("Anna","Smith"));
    managers.put(getPerson("Peter","Jones"));

    JSONObject response= new JSONObject();
    response.put("employees", employees );
    response.put("manager", managers );
    return response;
  }

---

请试试这个。。。希望能有帮助

JSONObject jsonObj1=null;
JSONObject jsonObj2=null;
JSONArray array=new JSONArray();
JSONArray array2=new JSONArray();

jsonObj1=new JSONObject();
jsonObj2=new JSONObject();


array.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));

array2.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));

jsonObj1.put("employees", array);
jsonObj1.put("manager", array2);

Response response = null;
response = Response.status(Status.OK).entity(jsonObj1.toString()).build();
return response;

---

也许还可以加入try/catch？（或者该方法必须有throws语句）JSONArray没有put方法。请使用add代替put@PT_Cyep JsonObject jo=Json.createObjectBuilder（）；jo.添加（“名字”、“约翰”）；添加（“姓氏”、“Doe”）；jo.build（）@ArnoldBrown为了向mainObj添加数组，它必须有一个键。