Java 子表的Hibernate软删除

假设我们有两个实体Customer和AppUser，它们是一对多关系

客户实体：

@Entity
@Table(name = "CUSTOMER")
//Override the default Hibernation delete and set the deleted flag rather than deleting the record from the db.
@SQLDelete(sql="UPDATE customer SET deleted = '1' WHERE id = ?")
//Filter added to retrieve only records that have not been soft deleted.
@Where(clause="deleted <> '1'")
public class Customer implements java.io.Serializable {
    private long id;
    private Billing billing;
    private String name;
    private String address;
    private String zipCode;
    private String city;
    private String state;
    private String notes;
    private char enabled;
    private char deleted;
    private Set appUsers = new HashSet(0);

    //Constructors...

    //Getters and Setters...

    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "customer")
    //Filter added to retrieve only records that have not been soft deleted.
    @Where(clause="deleted <> '1'")
    public Set getAppUsers() {
    return this.appUsers;
    }
    public void setAppUsers(Set appUsers) {
    this.appUsers = appUsers;
    }
}

@Entity
@Table(name = "APP_USER")
//Override the default Hibernation delete and set the deleted flag rather than deleting the record from the db.
@SQLDelete(sql="UPDATE app_user SET deleted = '1' WHERE id = ?")
//Filter added to retrieve only records that have not been soft deleted.
@Where(clause="deleted <> '1'")
public class AppUser implements java.io.Serializable {
    private long id;
    private Customer customer;
    private AppRole appRole;
    private char enabled;
    private String username;
    private String appPassword;
    private Date expirationDate;
    private String firstName;
    private String lastName;
    private String email;
    private String phone;
    private String fax;
    private char deleted;
    private Set
    persons = new HashSet(0);

    //Constructors...

    //Getters and Setters...
}

---

现在，已删除的appUser已从数据库中硬删除，并保留三条记录。我还是想用软删除来处理这种情况，有人可以帮忙吗？

最后，我找到了答案，添加@SQLDelete来收集客户类

@SQLDelete(sql="UPDATE customer SET deleted = '1' WHERE id = ?")
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "customer")
//Filter added to retrieve only records that have not been soft deleted.
@Where(clause="deleted <> '1'")
    public Set getAppUsers() {
    return this.appUsers;
}

@SQLDelete（sql=“UPDATE customer SET deleted='1'其中id=？”）
@OneToMany（cascade=CascadeType.ALL，fetch=FetchType.LAZY，mappedBy=“客户”）
//添加筛选器以仅检索尚未软删除的记录。
@其中（子句=“已删除的“1”）
公共集getAppUsers（）{
返回此.appUsers；
}

休眠文档链接：

---

谢谢！你是个救生员。

appUsers.remove(oneItem)

saveCustomer(customer);

@SQLDelete(sql="UPDATE customer SET deleted = '1' WHERE id = ?")
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "customer")
//Filter added to retrieve only records that have not been soft deleted.
@Where(clause="deleted <> '1'")
    public Set getAppUsers() {
    return this.appUsers;
}