Java 如何在数组中传递tribonacci系列值,然后打印我想要的任何索引值?
//节目:Tribonaci系列Java 如何在数组中传递tribonacci系列值,然后打印我想要的任何索引值?,java,arrays,windows,algorithm,indexing,Java,Arrays,Windows,Algorithm,Indexing,//节目:Tribonaci系列 import java.util.*; import java.io.*; class Tribonacci { public static void main(String args[]) { Scanner sc = new Scanner(System.in); System.out.print("Enter number till u want Tribonacci series: ");
import java.util.*;
import java.io.*;
class Tribonacci
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter number till u want Tribonacci series: ");
int n=sc.nextInt();
int a = 0,b = 0,c = 1;
int d = a+b+c;
System.out.println("\nTribonacci Series: ");
System.out.print(a+"\t"+b+"\t"+c);
for(int i=4;i<=n;i++)
{
System.out.print("\t"+d);
a=b;
b=c;
c=d;
d=a+b+c;
}
System.out.println();
}
}
import java.util.*;
导入java.io.*;
Tribonaci类
{
公共静态void main(字符串参数[])
{
扫描仪sc=新的扫描仪(System.in);
System.out.print(“输入数字直到您想要Tribonaci系列:”);
int n=sc.nextInt();
int a=0,b=0,c=1;
int d=a+b+c;
System.out.println(“\nTribonacci系列:”);
系统输出打印(a+“\t”+b+“\t”+c);
对于(int i=4;i您可以声明一个列表,并将生成的Tribonaci编号保存到该列表中。然后通过将索引1传递到n,可以访问任何Tribonaci编号
尝试使用此代码
public static void main(String args[]) {
Scanner sc = null;
try {
sc = new Scanner(System.in);
System.out.print("Enter number till u want Tribonacci series: ");
int n = sc.nextInt();
int a = 0, b = 0, c = 1;
int d = a + b + c;
List<Integer> triboList = new ArrayList<Integer>();
if(n <= 0) {
System.out.println("Invalid number. Number must be greater than zero");
return;
}
System.out.println("\nTribonacci Series: ");
if (n == 1) {
System.out.print(a);
triboList.add(a);
} else if (n == 2) {
System.out.print(a + "\t" + b);
triboList.add(a);
triboList.add(b);
} else if (n >= 3) {
triboList.add(a);
triboList.add(b);
triboList.add(c);
System.out.print(a + "\t" + b + "\t" + c);
}
for (int i = 4; i <= n; i++) {
System.out.print("\t" + d);
triboList.add(d);
a = b;
b = c;
c = d;
d = a + b + c;
}
System.out.println();
System.out.println("Enter a number between 1 and " + n + " to print tribonacci number for that index.");
int index = sc.nextInt();
if (index < 1 || index > n) {
System.out.println("Invalid index. Index can only be 1 to " + n);
} else {
System.out.println(triboList.get(index - 1));
}
} finally {
if (sc != null) {
sc.close();
}
}
}
publicstaticvoidmain(字符串参数[]){
扫描仪sc=空;
试一试{
sc=新扫描仪(系统英寸);
System.out.print(“输入数字直到您想要Tribonaci系列:”);
int n=sc.nextInt();
int a=0,b=0,c=1;
int d=a+b+c;
List=newarraylist();
如果(n=3){
增加(a);
增加(b);
添加(c);
系统输出打印(a+“\t”+b+“\t”+c);
}
对于(int i=4;i n){
System.out.println(“无效索引。索引只能是1到“+n”);
}否则{
System.out.println(triboList.get(index-1));
}
}最后{
如果(sc!=null){
sc.close();
}
}
}
很抱歉,php和c编程语言在这里有什么关系?因为上面的“代码”在Java中不要在你的问题中使用不相关的标记只是为了引起注意,请阅读,尤其是和。还有。兄弟,这是一个错误,非常欢迎并很高兴能提供帮助。另外,我已经用代码更新了答案,以便你的程序能够正确地处理所有类型的输入,负数以及1、2、3、4等等,即使在您为n的值输入了1或2,它至少打印了3个Tribonaci编号。