在深度优先搜索Java上向列表添加路径的边
我正在尝试在有向图上实现深度优先搜索算法。该图存在多个顶点(在深度优先搜索Java上向列表添加路径的边,java,Java,我正在尝试在有向图上实现深度优先搜索算法。该图存在多个顶点(V顶点),每个顶点都有一组边(E边)。每条边都有一个指向下一条边的指针(.getTo())和一个指向上一条边的指针(.getFrom())。我想找到从起始顶点到目标顶点的边的路径。为了存储和创建路径,我创建了一个helper类DGPath。我想用递归的方式来做这件事 在DGPath创建路径帮助器类下面: /** * represents a path of connected vertices and edges in the
V顶点
),每个顶点都有一组边(E边
)。每条边都有一个指向下一条边的指针(.getTo()
)和一个指向上一条边的指针(.getFrom()
)。我想找到从起始顶点到目标顶点的边的路径。为了存储和创建路径,我创建了一个helper类DGPath
。我想用递归的方式来做这件事
在DGPath
创建路径帮助器类下面:
/**
* represents a path of connected vertices and edges in the graph
*/
public class DGPath {
private V start = null;
private LinkedList<E> edges = new LinkedList<>();
private double totalWeight = 0.0;
private Set<V> visited = new HashSet<>();
/**
* representation invariants:
* 1. The edges are connected by vertices, i.e. FOR ALL i: 0 < i < edges.length: edges[i].from == edges[i-1].to
* 2. The path begins at vertex == start
* 3. if edges is empty, the path also ends at vertex == start
* otherwise edges[0].from == start and the path continues along edges[i].to for all 0 <= i < edges.length
**/
@Override
public String toString() {
StringBuilder sb = new StringBuilder(
String.format("Weight=%f Length=%d Visited=%d (",
this.totalWeight, 1 + this.edges.size(), this.visited.size()));
sb.append(start.getId());
for (E e : edges) {
sb.append(", " + e.getTo().getId());
}
sb.append(")");
return sb.toString();
}
public V getStart() {
return start;
}
public LinkedList<E> getEdges() {
return edges;
}
public double getTotalWeight() {
return totalWeight;
}
public Set<V> getVisited() {
return visited;
}
}
最后,在深度优先搜索方法的递归
辅助方法下面:
private void dfsHelper(V current, Set<V> discovered) {
discovered.add(current);
for (E edge : current.getEdges()) {
while(edge.getTo() != null){
V nextV = edge.getTo();
if (!discovered.contains(nextV)) {
dfsHelper(nextV, discovered);
}
}
}
}
private void dfsHelper(V当前,已发现集){
发现。添加(当前);
对于(E edge:current.getEdges()){
while(edge.getTo()!=null){
V nextV=edge.getTo();
如果(!discovered.contains(nextV)){
dfsHelper(nextV,已发现);
}
}
}
}
这段代码现在不工作,它一直停留在递归中
- 如何更改此代码以找到从起始顶点到目标顶点的正确路径
- 如何在
中保存用于从起点到目标的边DGPath.edges
path.visited.add(start)代码>
关于第二个问题,请为路径定义另一个字段,例如边,每当您向path.visted
添加新节点时,请将相应的边添加到path.edges
(不要忘记刷新path.edges,如每次迭代的path.visted
)
调用depthFirstSearch
后,path.visitored将具有您想要的内容。我通过保存边修复了工作算法:
DGPath帮助器类仍然与上面相同
DFS方法和Recrive“helper”:
我修正了方法(见我的答案),谢谢你的反应。帮助我朝着正确的方向思考!
private void dfsHelper(V current, Set<V> discovered) {
discovered.add(current);
for (E edge : current.getEdges()) {
while(edge.getTo() != null){
V nextV = edge.getTo();
if (!discovered.contains(nextV)) {
dfsHelper(nextV, discovered);
}
}
}
}
public DGPath depthFirstSearch(String startId, String targetId) {
// get node/vertex on ID
V start = this.getVertexById(startId);
V target = this.getVertexById(targetId);
// if they dont exist return null
if (start == null || target == null) return null;
// create new path
DGPath path = new DGPath();
// set starting node/vertex
path.start = start;
// easy target
if (start == target) {
path.visited.add(start);
return path;
}
// return the recursive method with starting point, target and the path
return dfsRecursive(path.start, target, path);
}
private DGPath dfsRecursive(V current, V target, DGPath path) {
// if node/vertex is already visited we have no path
if (path.getVisited().contains(current)) {
return null;
}
// add current node/vertex to visited set
path.getVisited().add(current);
// if we reach the destination we return the path
if (current.equals(target)) {
return path;
}
// else we go check all de edges connected to the vertex
for (E edge : current.getEdges()){
// if there is a new path we continue recursive until destination is reached
if (dfsRecursive(edge.getTo(), target, path) != null) {
// we add the edges as first in the set of edges to create the path
path.getEdges().addFirst(edge);
return path;
}
}
return null;
}