Java jcombobox未从数组加载值

}需要检查的事项：

查询是否实际返回了任何内容

行

jcombox1.setModel（客户）它在代码中的实际位置？如何创建客户？也许你需要发布这部分代码
传递给setmodel方法的customers对象是什么类型
根据我从您的代码中收集到的信息，您正在尝试将
字符串[]
设置为
JComboBox
的模型。这行不通。您可以将该数组包装在
DefaultComboxModel
中，如下所示：

jComboBox1.setModel(customers);


public class CustomerData {

private static final String JDBC_CONNECTION_URL = "jdbc:mysql://localhost/test";
private static final String DATABASE_USER       = "root";
private static final String DATABASE_PASSWORD   = "root";

// query to select customer data
private static final String SQL_FETCH_CUSTOMERS = "SELECT custName FROM customers";
private Connection connection = null;


public CustomerData(){
    initConnection();
}


private void initConnection() {
    try {
        //load the mysql driver
        Class.forName("com.mysql.jdbc.Driver");
        //create the database connection
        connection = DriverManager.getConnection(JDBC_CONNECTION_URL, DATABASE_USER, DATABASE_PASSWORD);
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    } catch (SQLException e) {
        e.printStackTrace();
    }

}

public void closeConnection(){
    if (connection != null) {
        try {
            connection.close();
        } catch (SQLException e) {
            e.printStackTrace();
        } finally {
            connection = null;
        }
    }
}


public ArrayList fetchCustomerData(){
    if (connection != null){
        Statement statement = null;
        try {
            statement = connection.createStatement();
            //get results from database
            ResultSet resultSet = statement.executeQuery(SQL_FETCH_CUSTOMERS);
            //get customers from resultset and return them to the app
            return convertResultSetToCustomersArray(resultSet);
        } catch (SQLException e) {
            e.printStackTrace();
        } finally {
            //close the statement we just used
            if (statement != null){
                try {
                    statement.close();
                } catch (SQLException e) {
                    e.printStackTrace();
                }
            }
        }
    }else{
        System.out.println("NO VALID DATABASE CONNECTION, CAN'T FETCH CUSTOMER DATA!");
    }
    return new ArrayList();
}

private ArrayList convertResultSetToCustomersArray(ResultSet results) throws SQLException{
    ArrayList customers = new ArrayList();

    //loop the results and add customers to an ArrayList
    while (results.next()){
        customers.add(results.getString("custName"));
    }
    return customers;
}
    private String[] customers = null;
    private void initData(){
    CustomerData customerData = new CustomerData();

    ArrayList custArrayList = customerData.fetchCustomerData();

    //get the array from the ArrayList and cast it to a String[]
    customers = (String[]) custArrayList.toArray(new String[0]);
}

这个问题的重点是什么？您已经为此主题创建了另一个帖子。您没有遵循该帖子中给出的建议。阅读这个问题的人不知道你想做什么，为什么你要浪费每个人的时间？这不是获得帮助的方法。嗯，修复了其中一些问题，现在它告诉我它找不到可变客户
jComboBox1.setModel(new DefaultComboBoxModel(customers));