Can'；我不明白这个java异常是什么；“主要”；java.lang.StringIndexOutOfBoundsException:字符串索引超出范围：1

我希望这个程序询问用户一个字符串和字符，然后告诉用户字符中的字符串数

代码如下：

import java.util.Scanner;  // Needed for the Scanner Class

/* 

This program ask you to enter a string and a character and then tells you how many times the character appears in the string. 

*/

public class PC5

{ public static void main(String[] args) throw StringIndexOutOfBoundsException


   {
      int times = 0;  // To keep track of the times the charcater appears in the String 
      String str1;    // To get the string you want to check
     String str2;   // To get the string for the character you want to check in the String.
      char myChar;  // To get the character from str2 


      Scanner keyboard = new Scanner(System.in);

      // Get the string you want to check 
      System.out.print("Enter the string you want to check: ");
      str1 = keyboard.nextLine();


      // To get the charcater
      System.out.print("Enter the character you want to check: ");
      str2 = keyboard.nextLine();
      myChar = str2.charAt(0); 

     for (int i = 0; i < str1.length(); i++)

         {
            if (str2.charAt(i) == myChar)
                    times += 1;


         }


         System.out.println("The number of times the character appears in the string is: " + times);


  }


  }

谢谢你的帮助。

你的意思可能是

if (str1.charAt(i) == myChar)

而不是

if (str2.charAt(i) == myChar)

---

当您在

str1

的长度上进行迭代，并期望

str2.length

等于

1

时，您可以使用一些字符串方法尝试更简洁的方法：

package com.example.count;

导入java.util.Scanner；//Scanner类所需的

/*

这个程序要求您输入一个字符串和一个字符，然后告诉您该字符在字符串中出现了多少次

*/

公共类PC5{

public static void main(String[] args)

{
    int times = 0; // To keep track of the times the charcater appears in
                    // the String
    String str1; // To get the string you want to check
    String str2; // To get the string for the character you want to check in
                    // the String.

    Scanner keyboard = new Scanner(System.in);

    // Get the string you want to check
    boolean stopping = false;
    while (!stopping) {
        System.out
                .print("Enter the string you want to check: (enter 'end' to stop)");
        str1 = keyboard.nextLine();
        stopping = "end".equalsIgnoreCase(str1.trim());
        if (!stopping) {

            // To get the character
            System.out.print("Enter the character you want to check: ");
            str2 = keyboard.nextLine();
            if (str2.length() > 1) {
                str2 = str2.substring(0, 1);
            }

            times = 0;
            int loc = -1;
            while ((loc = str1.indexOf(str2, loc + 1)) > -1) {
                times++;
            }

            System.out.println("Results: '" + str2 + "' appears " + times
                    + " times in string " + str1);
        }

    }
    keyboard.close();
    System.out.println("Thanks");

}

}

---

谢谢！我很惊讶我没听清楚，是的，这就是我的意思。我把它改为if（str1.charAt（I）=myChar），但我仍然得到了异常。这意味着（duh！）字符串索引超出了范围。做一点调试——你知道哪一行有错误，所以调试应该很简单。如果这有用，请标记答案“up”并“已回答”。对不起，我是新手，该怎么做？单击答案上的向上箭头符号并“检查”答案谢谢。我已检查过。

public static void main(String[] args)

{
    int times = 0; // To keep track of the times the charcater appears in
                    // the String
    String str1; // To get the string you want to check
    String str2; // To get the string for the character you want to check in
                    // the String.

    Scanner keyboard = new Scanner(System.in);

    // Get the string you want to check
    boolean stopping = false;
    while (!stopping) {
        System.out
                .print("Enter the string you want to check: (enter 'end' to stop)");
        str1 = keyboard.nextLine();
        stopping = "end".equalsIgnoreCase(str1.trim());
        if (!stopping) {

            // To get the character
            System.out.print("Enter the character you want to check: ");
            str2 = keyboard.nextLine();
            if (str2.length() > 1) {
                str2 = str2.substring(0, 1);
            }

            times = 0;
            int loc = -1;
            while ((loc = str1.indexOf(str2, loc + 1)) > -1) {
                times++;
            }

            System.out.println("Results: '" + str2 + "' appears " + times
                    + " times in string " + str1);
        }

    }
    keyboard.close();
    System.out.println("Thanks");

}

}