Java 实例化一行中的数组

我正在创建一个存储分层数据的Java类。它与XML非常相似，我将保留XML中的整个结构，以便稍后由Java解析，但我们希望避免I/O开销

相反，我希望将Java对象中硬编码的数据保存在全局变量中。XML代码如下所示：

<Group name="Order">
   <Milestone name="Tested" value="testedDate"/>
   <Milestone name="Created">
      <Milestone name="Delivered" value="deliveredDate"/>
      <Milestone name="Pressed" value="someString"/>
      <Milestone name="Assembled" value="whatever"/>
   </Milestone>
   <Milestone name="Ordered" value="something"/>
</Group>

Group[] groups = {
   new Group("Order",{
      new Milestone("Tested","testedDate"),
      new Milestone("Created",{
         new Milestone("Delivered","deliveredDate"),
         new Milestone("Pressed","someString"),
         new Milestone("Assembled","whatever")})
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

注意，里程碑元素可以有相同类型的子元素。因此，我创建了一个具有两个构造函数的里程碑类。第一个构造函数处理第一个里程碑元素。它只接受名称和值属性作为字符串输入。第二个构造函数将name属性作为字符串输入，并将里程碑对象数组作为第二个输入

public Milestone(String name, String value) { .....}
public Milestone(String name, Milestone[] subMilestones) { ...... }

但现在我要做的是在一行代码中实例化所有这些，如下所示：

<Group name="Order">
   <Milestone name="Tested" value="testedDate"/>
   <Milestone name="Created">
      <Milestone name="Delivered" value="deliveredDate"/>
      <Milestone name="Pressed" value="someString"/>
      <Milestone name="Assembled" value="whatever"/>
   </Milestone>
   <Milestone name="Ordered" value="something"/>
</Group>

Group[] groups = {
   new Group("Order",{
      new Milestone("Tested","testedDate"),
      new Milestone("Created",{
         new Milestone("Delivered","deliveredDate"),
         new Milestone("Pressed","someString"),
         new Milestone("Assembled","whatever")})
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

它似乎不喜欢那样。简言之，我不喜欢在组数组声明中打开括号来启动一个新的“新”里程碑对象数组。是否有一种方法可以在一行代码中完成这一切（例如，在一个声明中，末尾有一个分号）？

您必须显式地实例化子数组，如

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever")}),
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

必须显式实例化子数组，如中所示

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever")}),
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

必须显式实例化子数组，如中所示

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever")}),
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

必须显式实例化子数组，如中所示

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever")}),
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

从变量声明

Group[] groups = ...

编译器只知道

组

是

组

对象的数组。它不知道内部结构。尽管如此，此内部结构可以在单个语句中构建，但您必须声明它：

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever"))}
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

从变量声明

Group[] groups = ...

编译器只知道

组

是

组

对象的数组。它不知道内部结构。尽管如此，此内部结构可以在单个语句中构建，但您必须声明它：

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever"))}
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

从变量声明

Group[] groups = ...

编译器只知道

组

是

组

对象的数组。它不知道内部结构。尽管如此，此内部结构可以在单个语句中构建，但您必须声明它：

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever"))}
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

从变量声明

Group[] groups = ...

编译器只知道

组

是

组

对象的数组。它不知道内部结构。尽管如此，此内部结构可以在单个语句中构建，但您必须声明它：

Group[] groups = {
   new Group("Order", new Milestone[] {
      new Milestone("Tested","testedDate"),
      new Milestone("Created", new Milestone[] {
         new Milestone("Delivered,"deliveredDate"),
         new Milestone("Pressed,"someString"),
         new Milestone("Assembled,"whatever"))}
      new Milestone("Ordered","something")
   }
   new Group("Invoice",...
   ...
   ...
};

---

你可能忘了添加

），

@Braj我只是从原始问题中复制了几行。为了让机修工知道这已经足够了。其余部分隐藏在“…”:-）你可能忘了添加

），

@Braj我只是从原始问题中复制了几行。为了让机修工知道这已经足够了。其余部分隐藏在“…”:-）你可能忘了添加

），

@Braj我只是从原始问题中复制了几行。为了让机修工知道这已经足够了。其余部分隐藏在“…”:-）你可能忘了添加

），

@Braj我只是从原始问题中复制了几行。为了让机修工知道这已经足够了。其余部分隐藏在“…”:-）@谢谢，编译器给了我一些奇怪的信息，我真的无法解释问题是什么。我试过这样做，但Eclipse由于其他错误而无法正确更改文本的颜色。@Braj谢谢，编译器给了我一些奇怪的消息，我无法真正理解问题所在。我试过这样做，但Eclipse由于其他错误而无法正确更改文本的颜色。@Braj谢谢，编译器给了我一些奇怪的消息，我无法真正理解问题所在。我试过这样做，但Eclipse由于其他错误而无法正确更改文本的颜色。@Braj谢谢，编译器给了我一些奇怪的消息，我无法真正理解问题所在。我尝试过这样做，但是Eclipse由于其他错误而无法正确更改文本的颜色。