使用JPA查询的java.lang.ClassCastException
我正在尝试创建JavaEEWeb应用程序,但从数据库中获取单个结果时遇到问题。获取结果列表不是问题使用JPA查询的java.lang.ClassCastException,java,jpa,jakarta-ee,Java,Jpa,Jakarta Ee,我正在尝试创建JavaEEWeb应用程序,但从数据库中获取单个结果时遇到问题。获取结果列表不是问题 public UserCredentialsDTO findByUsernameAndPassword(String username, String password) { EntityManager em = getEntityManager(); TypedQuery<UserCredentialsDTO> q = em.createNam
public UserCredentialsDTO findByUsernameAndPassword(String username, String password) {
EntityManager em = getEntityManager();
TypedQuery<UserCredentialsDTO> q = em.createNamedQuery("UserCredentialsDTO.findByUsernameAndPassword", UserCredentialsDTO.class);
//Query q = em.createNamedQuery("UserCredentialsDTO.findByUsernameAndPassword", UserCredentialsDTO.class);
q.setParameter("un", username);
q.setParameter("pw", password);
UserCredentialsDTO r = null;
try{
r = q.getSingleResult(); //This line is a problem
//r = (UserCredentialsDTO)q.getSingleResult();
} catch(javax.persistence.NoResultException e) {
}
return r;
}
编辑
UserCredentialsDTO:
@NamedQueries(
{@NamedQuery(name = "UserCredentialsDTO.findByUsernameAndPassword", query = "select uc from UserCredentialsDTO uc where uc.username=:un and uc.password=:pw")}
)
@Entity
@Table(name="USERCREDENTIALS", schema="APP")
public class UserCredentialsDTO implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String username;
private String password;
@OneToMany(mappedBy = "userCredentials", cascade = CascadeType.ALL, fetch = FetchType.EAGER, orphanRemoval = true)
private List<UserGroupDTO> userGroups = new LinkedList<>();
//getters and setters
public void add(UserGroupDTO userGroup) {
userGroup.setUserCredentials(this);
this.userGroups.add(userGroup);
}
public List<UserGroupDTO> getUserGroups() {
return userGroups;
}
}
@namedquerys(
{@NamedQuery(name=“UserCredentialsDTO.findByUsernameAndPassword”,query=“从UserCredentialsDTO uc中选择uc,其中uc.username=:un和uc.password=:pw”)}
)
@实体
@表(name=“USERCREDENTIALS”,schema=“APP”)
实现可序列化的公共类UserCredentialsDTO{
@身份证
@GeneratedValue(策略=GenerationType.IDENTITY)
私人长id;
私有字符串用户名;
私有字符串密码;
@OneToMany(mappedBy=“userCredentials”,cascade=CascadeType.ALL,fetch=FetchType.EAGER,orphan=true)
private List userGroups=new LinkedList();
//接球手和接球手
public void add(UserGroupDTO userGroup){
userGroup.setUserCredentials(此);
this.userGroups.add(userGroup);
}
公共列表getUserGroups(){
返回用户组;
}
}
这看起来像是一个环境问题,JPA和应用程序的其余部分使用了不同的类加载器
您能将用户证书的代码发布到吗?也许对你有帮助。按你的意愿编辑
@NamedQueries(
{@NamedQuery(name = "UserCredentialsDTO.findByUsernameAndPassword", query = "select uc from UserCredentialsDTO uc where uc.username=:un and uc.password=:pw")}
)
@Entity
@Table(name="USERCREDENTIALS", schema="APP")
public class UserCredentialsDTO implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String username;
private String password;
@OneToMany(mappedBy = "userCredentials", cascade = CascadeType.ALL, fetch = FetchType.EAGER, orphanRemoval = true)
private List<UserGroupDTO> userGroups = new LinkedList<>();
//getters and setters
public void add(UserGroupDTO userGroup) {
userGroup.setUserCredentials(this);
this.userGroups.add(userGroup);
}
public List<UserGroupDTO> getUserGroups() {
return userGroups;
}
}