Java 根据拆分对列表进行排序

我有一个相当长的

字符串的
列表
：

test:test:test:test:test:test:test:ABC:test:test:test:test:test:test:  
test:test:test:test:test:test:test:DEF:test:test:test:test:test:test:  
test:test:test:test:test:test:test:GHI:test:test:test:test:test:test:  
test:test:test:test:test:test:test:JKL:test:test:test:test:test:test:  
test:test:test:test:test:test:test:MNO:test:test:test:test:test:test:  

假设所有测试彼此不同。我想根据大写字母所在的特定位置对这些字符串进行排序

    for (int i = 0; i < aList.size(); i++) {
        System.out.println(list.get(i).toString().split(":")[7]);
    }

for（int i=0；i
使用并提供自定义设置，以强制实施所需的订购标准

下面是一个示例（检查是否存在空值和意外格式ommited）：

列出myList；
Collections.sort（myList，newcomparator（）{
@凌驾
公共整数比较（字符串o1、字符串o2）{
字符串text1=o1.split（“：”[7]；
字符串text2=o2.split（“：”[7]；
返回text1.compareTo（text2）；
}
}); 
谢谢你，哈维。非常感谢。
List<String> myList;
Collections.sort(myList, new Comparator<String>(){
    @Override
    public int compare(String o1, String o2) {
        String text1 = o1.split(":")[7];
        String text2 = o2.split(":")[7];
        return text1.compareTo(text2);
    }
});