Spring3.2Servlet3.0Java配置（无web.xml）如何创建自定义404处理程序

在不使用

web.xml

的情况下，我必须捕获和处理404的哪些选项。以下是我定义Servlet的方式：

@Order(1)
public class MyWebApplicationInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    // 10MB
    private static final int MAX_UPLOAD_SIZE_IN_MB = 10 * 1024 * 1024;

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class[] { RootConfiguration.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class[] { WebConfiguration.class };
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }

    @Override
    protected Filter[] getServletFilters() {
        return new Filter[] { new SiteMeshFilter() };
    }

    @Override
    protected void customizeRegistration(ServletRegistration.Dynamic registration) {
        MultipartConfigElement multipartConfigElement = new MultipartConfigElement("/tmp", MAX_UPLOAD_SIZE_IN_MB, MAX_UPLOAD_SIZE_IN_MB * 2,
                MAX_UPLOAD_SIZE_IN_MB / 2);
        registration.setMultipartConfig(multipartConfigElement);
    }

}

然而

@ControllerAdvice
public class SomeClass {
...
    @ExceptionHandler(value = { ResourceNotFoundException.class, NoSuchRequestHandlingMethodException.class })
    public ModelAndView handle404() {
        ModelAndView modelAndView = new ModelAndView();
        modelAndView.setViewName("/errors/404");
        modelAndView.addObject("exception", "404 NOT FOUND!");
        return modelAndView;
    }
...
}

不捕捉404 我也试过HttpStatus。。。不走运

当我调用/someurl时，它不是文本列表：

[DEBUG] 2014-01-24 10:03:16,639 org.springframework.security.web.FilterChainProxy doFilter - /someUrlThatDoesNotExist reached end of additional filter chain; proceeding with original chain
[DEBUG] 2014-01-24 10:03:16,640 org.springframework.web.servlet.DispatcherServlet doService - DispatcherServlet with name 'dispatcher' processing GET request for [/someUrlThatDoesNotExist]
[DEBUG] 2014-01-24 10:03:16,641 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping getHandlerInternal - Looking up handler method for path /someUrlThatDoesNotExist
[DEBUG] 2014-01-24 10:03:16,662 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping getHandlerInternal - Did not find handler method for [/someUrlThatDoesNotExist]
[WARN] 2014-01-24 10:03:16,663 org.springframework.web.servlet.PageNotFound noHandlerFound - No mapping found for HTTP request with URI [/someUrlThatDoesNotExist] in DispatcherServlet with name 'dispatcher'
[DEBUG] 2014-01-24 10:03:16,665 org.springframework.web.servlet.DispatcherServlet processRequest - Successfully completed request

但当我尝试使用AOP检查以下切入点时：

org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver.handleHttpRequestMethodNotSupported(..)
org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver.handleNoSuchRequestHandlingMethod(..)

---

它们永远不会被捕获。

我认为您需要配置

DispatcherServlet

以在未找到处理程序时引发异常

dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);

---

然后让您的

@ControllerAdvice

为类型为

NoHandlerFoundException

的异常声明一个

@ExceptionHandler

异常处理程序。您有关于如何使用AbstractAnnotationConfigDispatchers ServletInitializer执行此操作的示例吗？@marcin我现在无权访问代码，但是该类应该有一个configureDispatcherServlet（）方法，您可以重写它。Sotirios Delimanolis我认为SetThroweExceptionIfNoHandlerFound只在spring 4.0中可用，而不是3.2.6 Dispatcherservlet仅在我看来像4.0。DispatcherServlet上有一个受保护的方法，您可以重写它，称为noHandlerFound。现在它只是将状态设置为404，您可以抛出一个异常instead@MarcinWasiluk我没有看到你的评论。如果不覆盖3.2.6中的一系列内容，您似乎无法做到这一点。

dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);