Java 如何在android中解析url

我有一个应该解析值的URL，但是当我给出

private static String url = "http://54.174.74.84/api/index/index?data={%20%22language_code%22:%22en_us%22,%20%22cmd%22:%22search_projects%22,%20%22user_device_id%22:319,%20%22page%22:0,%20%22user_token%22:%22edeN2y0EuakoD2deWGzijeuBQ5HRnhokyAqV4WIHzZz5PM0Qn2xgopKiAcboNJktgXeQMsX7kZmDW3T5Tta3i+Fz1mU5p1yTP1L3m\/OTGkOlDoJrLn6\/+I3rBqESDtFH%22,%20%22source_app%22:%22android%22,%20%22longitude%22:%22567%22,%20%22user_id%22:67,%20%22latitude%22:%22123%22,%20%22records_per_page%22:%2210%22,%20%22search_key%22:%22%22%20}";

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就像这样，它显示出错误。所以请帮帮我。谢谢。

您需要使用

Uri

类：

String uri = Uri.parse("http://54.174.74.84/api/index/index")
            .buildUpon()
            .appendQueryParameter("data", "{%20%22language_ ..... %22%22%20}")
            .appendQueryParameter("param2", value2)
            .appendQueryParameter("param3", value3)
            .build().toString();

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这不是一个错误。只需使用java编码器类进行字符串编码。在使用字符串之前，您必须先对其进行解码，如下面的代码所示

String url = "http://54.174.74.84/api/index/index?data={%20%22language_code%22:%22en_us%22,%20%22cmd%22:%22search_projects%22,%20%22user_device_id%22:319,%20%22page%22:0,%20%22user_token%22:%22edeN2y0EuakoD2deWGzijeuBQ5HRnhokyAqV4WIHzZz5PM0Qn2xgopKiAcboNJktgXeQMsX7kZmDW3T5Tta3i+Fz1mU5p1yTP1L3m/OTGkOlDoJrLn6/+I3rBqESDtFH%22,%20%22source_app%22:%22android%22,%20%22longitude%22:%22567%22,%20%22user_id%22:67,%20%22latitude%22:%22123%22,%20%22records_per_page%22:%2210%22,%20%22search_key%22:%22%22%20}";

String result = java.net.URLDecoder.decode(url, "UTF-8");

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它显示了什么错误？无效的转义序列（有效的是\b\t\n\f\r\“\\”\）tnx。我将尝试通过“不同的键”返回uif。您指的是不同的URL参数，然后需要通过调用

appendQueryParameter（）来追加它们

对于每个参数，请参见编辑后的答案：）我不知道如何解析代码。因为我是beginer。我遵循这个示例创建一个新问题并在此处发布链接：）