Java 如何更改OkHttp响应中的正文?
我正在使用改装。要捕获响应,我正在使用拦截器:Java 如何更改OkHttp响应中的正文?,java,android,retrofit,interceptor,okhttp,Java,Android,Retrofit,Interceptor,Okhttp,我正在使用改装。要捕获响应,我正在使用拦截器: OkHttpClient okHttpClient = new OkHttpClient(); okHttpClient.interceptors().add(myinterceptor); new Interceptor() { @Override public Response intercept(Chain chain) throws IOException { Request request = chain
OkHttpClient okHttpClient = new OkHttpClient();
okHttpClient.interceptors().add(myinterceptor);
new Interceptor() {
@Override
public Response intercept(Chain chain) throws IOException {
Request request = chain.request();
Response response = chain.proceed(request);
if (path.equals("/user")){
String stringJson = response.body().string();
JSONObject jsonObject = new JSONObject(stringJson);
jsonObject.put("key",1);
//here I need to set this new json to response and then return this response
以下是拦截器的代码:
OkHttpClient okHttpClient = new OkHttpClient();
okHttpClient.interceptors().add(myinterceptor);
new Interceptor() {
@Override
public Response intercept(Chain chain) throws IOException {
Request request = chain.request();
Response response = chain.proceed(request);
if (path.equals("/user")){
String stringJson = response.body().string();
JSONObject jsonObject = new JSONObject(stringJson);
jsonObject.put("key",1);
//here I need to set this new json to response and then return this response
如何在OkHttp响应中更改正文?添加此选项
MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject);
return response.newBuilder().body(body).build();
在您的回复修改后
jsonObject
是要返回的修改后的JSON。下面是响应拦截器类,您可以在其中截获OKHTTP响应并添加自己的响应。然后把它送去改装
import org.json.JSONException;
import org.json.JSONObject;
import java.io.IOException;
import okhttp3.Interceptor;
import okhttp3.MediaType;
import okhttp3.Request;
import okhttp3.ResponseBody;
import retrofit2.Response;
public class ApiResponseInterceptor implements Interceptor {
@Override
public okhttp3.Response intercept(Chain chain) throws IOException {
Request request = chain.request();
okhttp3.Response response = chain.proceed(request);
if(response.code() == 200) {
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("code",200);
jsonObject.put("status","OK");
jsonObject.put("message","Successful");
MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject.toString());
return response.newBuilder().body(body).build();
} catch (JSONException e) {
e.printStackTrace();
}
} else if(response.code() == 403) {
}
return response;
}
}
Yow将在您的改装回调中获得您修改的响应
call.enqueue(new Callback<EventResponce>() {
@Override
public void onResponse(Call<EventResponce> call, Response<EventResponce> response) {
// you will get your own modified responce here
}
@Override
public void onFailure(Call<EventResponce> call, Throwable t) {
}
});
call.enqueue(新回调(){
@凌驾
公共void onResponse(调用、响应){
//您将在此处获得自己的修改响应
}
@凌驾
失败时公共无效(调用调用,可丢弃的t){
}
});
作为一个小改动,我不会使用string()
方法,因为此请求只能调用一次。您确实使用了response.newBuilder()
,因此链下游的其他拦截器将能够在您的新拦截器上调用string()
,但我发现自己浪费了几个小时,因为我实际上调用了它两次:P
所以我建议如下
BufferedSource source = response.body().source();
source.request(Long.MAX_VALUE); // Buffer the entire body.
Buffer buffer = source.buffer();
String responseBodyString = buffer.clone().readString(Charset.forName("UTF-8"));
下面是一个添加拦截器的完整示例,该拦截器将JSON修改为。它用于管理JSON
client.addInterceptor(chain -> {
final Request request = chain.request();
final String path = request.url().uri().getPath();
final Response response = chain.proceed(request);
String body = response.body().string();
final JsonElement element = new JsonParser().parse(body);
if ("/the/endpoint/you/want/to/modify".equals(path)){
final JsonObject object = element.getAsJsonObject();
// v v v v v v All this for these lines v v v v v v v
object.addProperty("some_json_name","some_json_value");
object.addProperty("existing_property","updated_value");
object.addProperty("numbers_work_too",1.2);
// ^ ^ ^ ^ ^ ^ All this for these lines ^ ^ ^ ^ ^ ^ ^
body = object.toString();
}
return response.newBuilder().body(ResponseBody.create(response.body().contentType(), body)).build();
});
您面临的问题是什么?我需要将这个新的json设置为response,然后返回这个响应,怎么做?