如何使用Java检查两个矩形几何图形之间的空间关系
所以我有一个程序需要测试两个矩形并检查:如何使用Java检查两个矩形几何图形之间的空间关系,java,geometry,Java,Geometry,所以我有一个程序需要测试两个矩形并检查: 如果测试矩形在参考矩形内 如果测试矩形与参考矩形重叠 如果测试矩形仅与参考矩形共享边框 如果测试矩形和参考矩形不同 参考矩形和测试矩形均使用其中心坐标(x,y)及其宽度和高度进行定义 我相信我的第一个检查编码正确,但我无法计算出重叠、共享边界和完全不同的最后三个检查的数学 以下是我迄今为止四项检查的代码: //returns true if the specified rectangle is inside this rectangle
//returns true if the specified rectangle is inside this rectangle
public boolean contains(MyRectangle2D r){
if(this.x > r.x + r.width && x + width < r.x && y > r.y +r.height && y + height < r.y){
return true;
}
else{
return false;
}
}
//returns true if the specified rectangle overlaps with this rectangle
public boolean overlaps(MyRectangle2D r) {
if (this.x < r.x + r.width && x + width > r.x && y < r.y + r.height && y + height > r.y){
return true;
}
else{
return false;
}
}
//returns true if only the boundaries touch
public boolean abut(MyRectangle2D r) {
if(this.x = r.x + r.width && x + width = r.x || y = r.y +r.height && y + height = r.y){
return true;
}
else{
return false;
}
}
//returns true if the rectangles are not touching at all
public boolean distinct(MyRectangle2D r) {
}
//如果指定的矩形在此矩形内,则返回true
公共布尔包含(MyRectangler){
如果(此.x>r.x+r.width&&x+widthr.y+r.height&&y+heightr.x&&yr.y){
返回true;
}
否则{
返回false;
}
}
//如果仅边界接触,则返回true
公共布尔邻接(MyRectangler){
如果(此.x=r.x+r.width&&x+width=r.x | | y=r.y+r.height&&y+height=r.y){
返回true;
}
否则{
返回false;
}
}
//如果矩形完全不接触,则返回true
公共布尔值独立(MyRectangler){
}
您可以使用Java Topology套件()来实现:
- 首先,您可以使用
()创建带有参数的矩形:org.locationtech.jts.util.GeometricShapeFactory
- 然后您可以使用
()org.locationtech.jts.geom.Geometry
// method to create your rectangles like before (Polygon objects)
public static Polygon createPolygon(Coordinate center, double width, double height){
GeometricShapeFactory shapeFactory = new GeometricShapeFactory();
shapeFactory.setNumPoints(4);
shapeFactory.setCentre(center);
shapeFactory.setWidth(width);
shapeFactory.setHeight(height);
return shapeFactory.createRectangle();
}
public static void main(String[] args) {
// create your rectagles
Polygon rectangleA = createPolygon(new Coordinate(0, 0), 5, 10);
Polygon rectangleB = createPolygon(new Coordinate(2, 0), 5, 10);
// ### check your constraints
// 1. rectangle is within the reference rectangle
boolean bWithinA = rectangleB.within(rectangleA); // false
// 2. rectangle is overlapping the reference rectangle
boolean bOverlappingA = rectangleB.overlaps(rectangleA); // true
// 3. rectangle is only sharing a border with the reference rectangle
boolean bSharesBorderA = rectangleB.touches(rectangleA); // false
// 4. rectangle and reference rectangle are distinct
boolean bDistinctsA = rectangleB.disjoint(rectangleA); // false
}
您可以使用Java Topology套件()来实现:
- 首先,您可以使用
()创建带有参数的矩形:org.locationtech.jts.util.GeometricShapeFactory
- 然后您可以使用
()org.locationtech.jts.geom.Geometry
// method to create your rectangles like before (Polygon objects)
public static Polygon createPolygon(Coordinate center, double width, double height){
GeometricShapeFactory shapeFactory = new GeometricShapeFactory();
shapeFactory.setNumPoints(4);
shapeFactory.setCentre(center);
shapeFactory.setWidth(width);
shapeFactory.setHeight(height);
return shapeFactory.createRectangle();
}
public static void main(String[] args) {
// create your rectagles
Polygon rectangleA = createPolygon(new Coordinate(0, 0), 5, 10);
Polygon rectangleB = createPolygon(new Coordinate(2, 0), 5, 10);
// ### check your constraints
// 1. rectangle is within the reference rectangle
boolean bWithinA = rectangleB.within(rectangleA); // false
// 2. rectangle is overlapping the reference rectangle
boolean bOverlappingA = rectangleB.overlaps(rectangleA); // true
// 3. rectangle is only sharing a border with the reference rectangle
boolean bSharesBorderA = rectangleB.touches(rectangleA); // false
// 4. rectangle and reference rectangle are distinct
boolean bDistinctsA = rectangleB.disjoint(rectangleA); // false
}