Java 我的扫描仪/终端窗口在重复一次后停止工作

我目前正在gridworld上进行一个塔防项目（不确定这是否重要）。我有一个计时器，它从我的主类调用一个方法（

TowerPlacer

），通过扫描仪接收用户文本输入。但是，在第一次通过后，终端窗口停止允许我输入文本，尽管

TowerPlacer

计时器正在运行

此外，无论出于何种原因，该方法似乎也能阻止所有bug的产生。尽管这座塔实际上什么也没做

下面是TowerPlacer的方法

public static void TowerPlacer ()
{
  System.out.println ("You have " + money + " gold");
  Scanner kbReader = new Scanner(System.in);
  System.out.println ("Would you like to place a defense?");
  System.out.println ("1. Yes");
  System.out.println ("2. No");
  answer = kbReader.nextInt();
  kbReader.nextLine();
  if (answer == 1) {
    System.out.println ("Which defense would you like to place?");
    System.out.println ("1. Study defense - 50 gold");
    System.out.println ("2. Pencil defense - 100 gold");
    System.out.println ("3. Pen defense - 150 gold");
    System.out.println ("4. Cram defense - 200 gold");
    Tanswer = kbReader.nextInt();
    kbReader.nextLine();
    System.out.println ("Defenses cannot be placed in the path of the critters.");
    System.out.println ("Defenses not placed in viable locations will end the game.");
    System.out.println ("What is the X-coordinate of the defense? (0 - 9)");
    xCoord = kbReader.nextInt();
    kbReader.nextLine();
    System.out.println ("What is the Y-coordinate of the defense? (0 - 9)");
    yCoord = kbReader.nextInt();
    kbReader.nextLine();
    if (Tanswer == 1) {
      Study defense1 = new Study();
      world.add(new Location(xCoord, yCoord), defense1);
      System.out.println ("Defense Placed");
    }
    if (Tanswer == 2) {
      Study defense2 = new Study();
      world.add(new Location(xCoord, yCoord), defense2);
      System.out.println ("Defense Placed");
    }
    if (Tanswer == 3) {
      Study defense3 = new Study();
      world.add(new Location(xCoord, yCoord), defense3);
      System.out.println ("Defense Placed");
    }
    if (Tanswer == 4) {
      Study defense4 = new Study();
      world.add(new Location(xCoord, yCoord), defense4);
      System.out.println ("Defense Placed");
    }
  }
  if (answer == 2) {
    System.out.println ("Construction cancelled");
  }
  if (answer != 1 && answer != 2) {
    System.out.println ("Error, answer out of bounds");
  }
  System.gc();
}

这是我的计时器调用程序的代码

public static void main(String[] args)
{
  Timer timer = new Timer();
  TimerA a = new TimerA();
  timer.schedule(a,0,2000);
  TimerC t = new TimerC();
  timer.schedule(t,0,2000);
  world.show();
  System.out.println ("Please do not pause the game after starting.");
  TowerPlacer();
}

计时器本身

class TimerA extends TimerTask
{
  public static int times = 0;
  public void run()
  {
    times++;
    if (times%10 == 0) {
      BoxBugRunner.TowerPlacer();
    }
    if (times >= 1000000) {
      //Stop Timer.
      this.cancel();
    }
  }
}

---

错误在你的计时器任务中。您需要的是：

class SayHello extends TimerTask {

    public void run()
    {
      System.out.println("done");
    }

 }

然后将主要方法更改如下：

public static void main(String[] args)
{
    int delay = 2000; // delay for 2 seconds
    int period = 500; // repeat every .5 seconds

    Timer timer = new Timer();
    timer.scheduleAtFixedRate(new SayHello(), delay, period);
}

---

如果

计时器已经调用了
TowerPlacer（）
，为什么你自己在main中调用它呢？游戏开始时，我在main中调用了TowerPlacer（），以便玩家可以立即放置塔，然后计时器继续调用它。嗨！谢谢你的快速回复！这修复了产生的bug，但是终端窗口现在根本不接收任何输入（与以前相反，它在锁定之前只接受一次输入）。对不起，回复太晚了，昨天在舞会上很忙哈哈。我在gridworld外分别用定时器和kbReader做了一个测试，但我仍然遇到无法在终端中输入扫描仪的问题。别管！我用一个非常奇怪的while循环解决了终端窗口问题。无论我做了什么，终端窗口都不允许我在计时器运行时输入，但我通过一个几乎无限输出的while循环来解锁窗口。。。看不出背后的逻辑，但它是有效的！不过我很感激你们的回答，它解决了我在繁殖塔楼时虫子不繁殖的问题！