Java 将字符串数组更改为整数
我正在尝试创建一个方法来获取字符串数组,并将元素复制到整数数组中,然后计算平均值。不确定我是走对了路还是完全错了Java 将字符串数组更改为整数,java,arrays,Java,Arrays,我正在尝试创建一个方法来获取字符串数组,并将元素复制到整数数组中,然后计算平均值。不确定我是走对了路还是完全错了 public static double CalculateAvg(String [] Grades) { int []Exams = new int[Grades.length]; double AVG =0; int sum = 0; int j = 0; for (int i = 0; i <= Grades.length;
public static double CalculateAvg(String [] Grades)
{
int []Exams = new int[Grades.length];
double AVG =0;
int sum = 0;
int j = 0;
for (int i = 0; i <= Grades.length; i++)
{
Exams[i] = Integer.parseInt(Grades[i]);
Exams[i] = j;
sum +=j;
AVG= (double)sum/4;
}
//return AVG;
}
}
公共静态双重计算avg(字符串[]等级)
{
int[]考试=新的int[成绩.长度];
双平均值=0;
整数和=0;
int j=0;
对于(int i=0;i您有很多冗余变量。请尝试:
public static double CalculateAvg(String [] Grades) {
double sum = 0;
for (int i = 0; i < Grades.length; i++) {
sum += Integer.parseInt(Grades[i]);
}
return sum/Grades.length;
}
要计算平均值,需要除以元素数
我想这就是你要找的
public static double CalculateAvg(String [] Grades)
{
int []Exams = new int[Grades.length];
double AVG =0;
int sum = 0;
int j = 0;
for (int i = 0; i <= Grades.length; i++)
{
Exams[i] = Integer.parseInt(Grades[i]);
AVG= (double) Exams[i]/Grades.length;
}
return AVG;
}
公共静态双重计算avg(字符串[]等级)
{
int[]考试=新的int[成绩.长度];
双平均值=0;
整数和=0;
int j=0;
对于(inti=0;i,您还可以尝试Java 8流和Lambda表达式,如下图所示:
public static double calculateAverage(String[] grades)
{
return Arrays.stream(grades)
.map(grade->Double.parseDouble(grade))
.reduce(0.0,(sum, grade) -> sum + grade)/grades.length;
}
为什么需要int j
变量?为什么要除以4?
public static double calculateAverage(String[] grades)
{
return Arrays.stream(grades)
.map(grade->Double.parseDouble(grade))
.reduce(0.0,(sum, grade) -> sum + grade)/grades.length;
}