在java中，根据玩家的用户输入和每个玩家的牌返回一副牌

我有一副牌洗牌和返回结果，但现在我想根据用户输入改变输出：玩家数量和每个玩家的牌数

原始代码：

CardRun-main

public static void main(String[] args)
{
    Scanner scan = new Scanner(System.in);
    Deck deck = new Deck();
    Card C;

    System.out.println(deck.getTotalCards());
    System.out.print("Number of players: ");
    int players = scan.nextInt();
    System.out.print("Number of cards: ");
    int cards = scan.nextInt();

    while(deck.getTotalCards() != players)
    {
        C = deck.drawFromDeck();
        System.out.println(C.toString());
    }

}

甲板等级

public class Deck {
private ArrayList<Card>cards;

Deck()
{
    cards = new ArrayList<Card>();
    for(int a=0; a<=3; a++)
    {
        for(int b=0; b<=12; b++)
        {
            cards.add(drawFromDeck());
        }
        cards.addAll(cards);
    }
}

public Card drawFromDeck()
{
    Random generator = new Random();
    int index = generator.nextInt(cards.size());
    return cards.remove(index);
}

public int getTotalCards()
{
    return cards.size();
}

}

public class Card {
private int card, suit;
private static String[] suits = {"Clubs", "Diamonds", "Hearts", "Spades"};
private static String[] cards = {"Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King"};

Card(int suit, int card)
{
    this.card = card;
    this.suit = suit;
}

public @Override String toString()
{
    for(int i = 0; i<players; ++i)
    {
        System.out.println("Player " + (i+1) + ": "+ cards.get(i));
    }
}

public int getCard()
{
    return card;
}

public int getSuit()
{
    return suit;
}
}

公共类甲板{
私人阵列列表卡；
甲板（）
{
cards=新的ArrayList（）；
对于（inta=0；a，如我所见，你让每个玩家从牌堆中抽出
牌
牌：

List<Hand> hands = new ArrayList<Hand>(players); // defines each players hand (in your case one, each "cards" cards);

// let 'em draw
for(int k=0; k<players; ++k) {
    Hand currentHand = new Hand();
    for(int i=0; i<cards; ++i) {
       currentHand.add(deck.drawFromDeck());
    }
    hands.add(currentHand);
}

// find the best
Collections.sort(hands); // make sure to implement Comparable, to reasonably check which one has the best hand

for(int i=0; i<players; ++i) {
    System.out.println("Player " + (i+1) + ": " + hands.get(i)); // Make sure Hand::toString() is overriden properly
}

List hands=new ArrayList（players）；//定义每个玩家的手牌（在您的示例中，每个“卡”牌）；
//让他们画
对于（int k=0；k请更具体地说明一天结束时输出的样子：）@poitroae添加了所需的输出格式。感谢您的帮助。每位玩家是否不只是获得3张卡？用户是否可以通过使用扫描仪决定玩家的数量以及输入中的卡数。但我将继续应用您提供的内容，并了解如何使用goes@Amina是的，这只是另外一个参数，这个设计没有问题。我编辑了它。所以d这是否意味着我必须将我当前使用的数组转换为arrayList？同时，我正在将这些更改添加到deck类中。是的，使用arrayList毕竟会更容易。好的..所以我用您提供的更新了上面的代码，如果可能的话，再看一看..我的头没有包得更满，因为我正在处理它，如果你可以指出任何错误，请做。我真的很感激。